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How do I start an “if” function in shell that requires the user to input between 4-9 parameters
The Next CEO of Stack OverflowHow to display the Linux kernel command line parameters given for the current boot?How to exit out of the shell script successfully so that python subprocess think it is successfull exit?change the extension of all files based on user inputDisplay a line in a text file if variable matches a part in the line?Pass command line parameters to a program inside the shell scriptHow to repeat a command n times then exit?Capturing the user input without requiring “Enter”(Shell Scripting) - Modify files with user inputArguments in `bash -c mycommand arg1 arg2`How can I extract a function from bash/zsh with all its shell-related dependencies?
I needto see if between 4 and 9 arguments were entered at the command line. Then if so display the first and the third and exit with a code equal to the number of arguments on the command line
linux bash
asked 2 days ago
user344036user344036
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I needto see if between 4 and 9 arguments were entered at the command line. Then if so display the first and the third and exit with a code equal to the number of arguments on the command line
linux bash
asked 2 days ago
user344036user344036
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
Since this seems semi-arbitrary, have you learned anything about UNIX shells recently that would help you along this path? What have you tried and what were the results?
– Jeff Schaller♦
2 days ago
1
Some related reading: Positional Parameters, Conditional Constructs, Bash Builtin Commands, Bourne Builtin Commands
– Jesse_b
2 days ago
add a comment |
I needto see if between 4 and 9 arguments were entered at the command line. Then if so display the first and the third and exit with a code equal to the number of arguments on the command line
linux bash
asked 2 days ago
user344036user344036
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I needto see if between 4 and 9 arguments were entered at the command line. Then if so display the first and the third and exit with a code equal to the number of arguments on the command line
linux bash
linux bash
asked 2 days ago
user344036user344036
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
user344036user344036
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
user344036user344036
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
user344036user344036
1
asked 2 days ago
user344036user344036
1
1
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user344036 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
Since this seems semi-arbitrary, have you learned anything about UNIX shells recently that would help you along this path? What have you tried and what were the results?
– Jeff Schaller♦
2 days ago
1
Some related reading: Positional Parameters, Conditional Constructs, Bash Builtin Commands, Bourne Builtin Commands
– Jesse_b
2 days ago
add a comment |
3
Since this seems semi-arbitrary, have you learned anything about UNIX shells recently that would help you along this path? What have you tried and what were the results?
– Jeff Schaller♦
2 days ago
1
Some related reading: Positional Parameters, Conditional Constructs, Bash Builtin Commands, Bourne Builtin Commands
– Jesse_b
2 days ago
3
3
Since this seems semi-arbitrary, have you learned anything about UNIX shells recently that would help you along this path? What have you tried and what were the results?
– Jeff Schaller♦
2 days ago
Since this seems semi-arbitrary, have you learned anything about UNIX shells recently that would help you along this path? What have you tried and what were the results?
– Jeff Schaller♦
2 days ago
1
1
Some related reading: Positional Parameters, Conditional Constructs, Bash Builtin Commands, Bourne Builtin Commands
– Jesse_b
2 days ago
Some related reading: Positional Parameters, Conditional Constructs, Bash Builtin Commands, Bourne Builtin Commands
– Jesse_b
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
This sounds like a homework assignment, so I will give all the bits of the puzzle that you need to solve it.
- The number of arguments are kept in the special variable
$#. - The third argument is
$3. To see whether a variable
$varis between 3 and 19 (inclusively), useif [ "$var" -ge 3 ] && [ "$var" -le 19 ]; then ...; fiwhere
...is the action you'd like to take if the statement is
true.Explicitly exiting from a script is done with
exit. Explicitly returning from a function is done withreturn. Both of these take an optional exit status.
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
1
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
add a comment |
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1 Answer
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1 Answer
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This sounds like a homework assignment, so I will give all the bits of the puzzle that you need to solve it.
- The number of arguments are kept in the special variable
$#. - The third argument is
$3. To see whether a variable
$varis between 3 and 19 (inclusively), useif [ "$var" -ge 3 ] && [ "$var" -le 19 ]; then ...; fiwhere
...is the action you'd like to take if the statement is
true.Explicitly exiting from a script is done with
exit. Explicitly returning from a function is done withreturn. Both of these take an optional exit status.
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
1
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
add a comment |
This sounds like a homework assignment, so I will give all the bits of the puzzle that you need to solve it.
- The number of arguments are kept in the special variable
$#. - The third argument is
$3. To see whether a variable
$varis between 3 and 19 (inclusively), useif [ "$var" -ge 3 ] && [ "$var" -le 19 ]; then ...; fiwhere
...is the action you'd like to take if the statement is
true.Explicitly exiting from a script is done with
exit. Explicitly returning from a function is done withreturn. Both of these take an optional exit status.
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
1
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
add a comment |
This sounds like a homework assignment, so I will give all the bits of the puzzle that you need to solve it.
- The number of arguments are kept in the special variable
$#. - The third argument is
$3. To see whether a variable
$varis between 3 and 19 (inclusively), useif [ "$var" -ge 3 ] && [ "$var" -le 19 ]; then ...; fiwhere
...is the action you'd like to take if the statement is
true.Explicitly exiting from a script is done with
exit. Explicitly returning from a function is done withreturn. Both of these take an optional exit status.
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
This sounds like a homework assignment, so I will give all the bits of the puzzle that you need to solve it.
- The number of arguments are kept in the special variable
$#. - The third argument is
$3. To see whether a variable
$varis between 3 and 19 (inclusively), useif [ "$var" -ge 3 ] && [ "$var" -le 19 ]; then ...; fiwhere
...is the action you'd like to take if the statement is
true.Explicitly exiting from a script is done with
exit. Explicitly returning from a function is done withreturn. Both of these take an optional exit status.
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
edited 2 days ago
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
answered 2 days ago
Kusalananda♦Kusalananda
138k17258428
138k17258428
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
1
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
add a comment |
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
1
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
Thank you so much it worked. I was having trouble wrapping my head around getting the range I was trying to do "$# -eq 4-9" , then I was trying to do it similar to your approach but using the -o flag.
– user344036
2 days ago
1
1
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
@user344036 If Kusalananda's answer was helpful to you, it's courteous to mark the answer as "Accepted."
– Jim L.
yesterday
add a comment |
user344036 is a new contributor. Be nice, and check out our Code of Conduct.
user344036 is a new contributor. Be nice, and check out our Code of Conduct.
user344036 is a new contributor. Be nice, and check out our Code of Conduct.
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3
Since this seems semi-arbitrary, have you learned anything about UNIX shells recently that would help you along this path? What have you tried and what were the results?
– Jeff Schaller♦
2 days ago
1
Some related reading: Positional Parameters, Conditional Constructs, Bash Builtin Commands, Bourne Builtin Commands
– Jesse_b
2 days ago