Python scanner for the first free port in a rangePython Port ScannerPython Port Scanner 2.0Python Port Scanner 2.1Simple C Port ScannerIP Range Port ScannerIP Scanner via python socketsPython proxy checker/scannerThe start of a Python port scannerPython port scanner using multithreadingSimple port scanner in Python 3
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Python scanner for the first free port in a range
Python Port ScannerPython Port Scanner 2.0Python Port Scanner 2.1Simple C Port ScannerIP Range Port ScannerIP Scanner via python socketsPython proxy checker/scannerThe start of a Python port scannerPython port scanner using multithreadingSimple port scanner in Python 3
$begingroup$
I have a distributed application (YARN), which runs a WebApp.
This application use a default port to start (8008), before I start I need to check if port is in use.
A container may run in the same virtual machine, hence port may be in use.
(Max I have 4 containers in WebApp).
I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.
def port_in_use(port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1', port))
if result == 0:
return True
else:
return False
def start_dashboard():
base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
scan_ports = True
attempts = 0
max_attempts = 10
while(scan_ports and attempts <= max_attempts):
if port_in_use(base_port):
base_port += 1
attempts += 1
else:
scan_ports = False
if attempts == max_attempts:
raise IOError('Port in use')
dashboard.configure(port=base_port)
dashboard.launch()
python python-3.x networking socket
$endgroup$
add a comment |
$begingroup$
I have a distributed application (YARN), which runs a WebApp.
This application use a default port to start (8008), before I start I need to check if port is in use.
A container may run in the same virtual machine, hence port may be in use.
(Max I have 4 containers in WebApp).
I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.
def port_in_use(port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1', port))
if result == 0:
return True
else:
return False
def start_dashboard():
base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
scan_ports = True
attempts = 0
max_attempts = 10
while(scan_ports and attempts <= max_attempts):
if port_in_use(base_port):
base_port += 1
attempts += 1
else:
scan_ports = False
if attempts == max_attempts:
raise IOError('Port in use')
dashboard.configure(port=base_port)
dashboard.launch()
python python-3.x networking socket
$endgroup$
add a comment |
$begingroup$
I have a distributed application (YARN), which runs a WebApp.
This application use a default port to start (8008), before I start I need to check if port is in use.
A container may run in the same virtual machine, hence port may be in use.
(Max I have 4 containers in WebApp).
I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.
def port_in_use(port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1', port))
if result == 0:
return True
else:
return False
def start_dashboard():
base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
scan_ports = True
attempts = 0
max_attempts = 10
while(scan_ports and attempts <= max_attempts):
if port_in_use(base_port):
base_port += 1
attempts += 1
else:
scan_ports = False
if attempts == max_attempts:
raise IOError('Port in use')
dashboard.configure(port=base_port)
dashboard.launch()
python python-3.x networking socket
$endgroup$
I have a distributed application (YARN), which runs a WebApp.
This application use a default port to start (8008), before I start I need to check if port is in use.
A container may run in the same virtual machine, hence port may be in use.
(Max I have 4 containers in WebApp).
I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.
def port_in_use(port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1', port))
if result == 0:
return True
else:
return False
def start_dashboard():
base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
scan_ports = True
attempts = 0
max_attempts = 10
while(scan_ports and attempts <= max_attempts):
if port_in_use(base_port):
base_port += 1
attempts += 1
else:
scan_ports = False
if attempts == max_attempts:
raise IOError('Port in use')
dashboard.configure(port=base_port)
dashboard.launch()
python python-3.x networking socket
python python-3.x networking socket
edited yesterday
200_success
130k17155419
130k17155419
asked yesterday
spicyramenspicyramen
307312
307312
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Your code has some incorrect assumptions.
an application may listen on a specific address/port combination;
127.0.0.1:port
can be available while*:port
is not.an application may bind a port without listening. Connects will fail, but so will your own bind.
a firewall or other mechanism can interfere with connections, generating false positives in your scan.
The reliable approach is to bind the port, just as your dashboard will, and then release it.
result = sock.bind(('', port))
sock.close()
You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard
logic cleaner and get rid of boolean loop-terminator scan_ports
. Just exit the loop by return
ing the answer.
def next_free_port( port=1024, max_port=65535 ):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
while port <= max_port:
try:
sock.bind(('', port))
sock.close()
return port
except OSError:
port += 1
raise IOError('no free ports')
def start_dashboard():
# pass optional second parameter "max_port" here, else scan until a free one is found
port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )
dashboard.configure(port=port)
dashboard.launch()
You can use netcat to make ports in-use for testing: nc -l -p 9999
will listen on port 9999; press control-C to end it.
$endgroup$
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
1
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
1
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
|
show 1 more comment
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your code has some incorrect assumptions.
an application may listen on a specific address/port combination;
127.0.0.1:port
can be available while*:port
is not.an application may bind a port without listening. Connects will fail, but so will your own bind.
a firewall or other mechanism can interfere with connections, generating false positives in your scan.
The reliable approach is to bind the port, just as your dashboard will, and then release it.
result = sock.bind(('', port))
sock.close()
You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard
logic cleaner and get rid of boolean loop-terminator scan_ports
. Just exit the loop by return
ing the answer.
def next_free_port( port=1024, max_port=65535 ):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
while port <= max_port:
try:
sock.bind(('', port))
sock.close()
return port
except OSError:
port += 1
raise IOError('no free ports')
def start_dashboard():
# pass optional second parameter "max_port" here, else scan until a free one is found
port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )
dashboard.configure(port=port)
dashboard.launch()
You can use netcat to make ports in-use for testing: nc -l -p 9999
will listen on port 9999; press control-C to end it.
$endgroup$
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
1
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
1
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
|
show 1 more comment
$begingroup$
Your code has some incorrect assumptions.
an application may listen on a specific address/port combination;
127.0.0.1:port
can be available while*:port
is not.an application may bind a port without listening. Connects will fail, but so will your own bind.
a firewall or other mechanism can interfere with connections, generating false positives in your scan.
The reliable approach is to bind the port, just as your dashboard will, and then release it.
result = sock.bind(('', port))
sock.close()
You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard
logic cleaner and get rid of boolean loop-terminator scan_ports
. Just exit the loop by return
ing the answer.
def next_free_port( port=1024, max_port=65535 ):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
while port <= max_port:
try:
sock.bind(('', port))
sock.close()
return port
except OSError:
port += 1
raise IOError('no free ports')
def start_dashboard():
# pass optional second parameter "max_port" here, else scan until a free one is found
port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )
dashboard.configure(port=port)
dashboard.launch()
You can use netcat to make ports in-use for testing: nc -l -p 9999
will listen on port 9999; press control-C to end it.
$endgroup$
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
1
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
1
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
|
show 1 more comment
$begingroup$
Your code has some incorrect assumptions.
an application may listen on a specific address/port combination;
127.0.0.1:port
can be available while*:port
is not.an application may bind a port without listening. Connects will fail, but so will your own bind.
a firewall or other mechanism can interfere with connections, generating false positives in your scan.
The reliable approach is to bind the port, just as your dashboard will, and then release it.
result = sock.bind(('', port))
sock.close()
You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard
logic cleaner and get rid of boolean loop-terminator scan_ports
. Just exit the loop by return
ing the answer.
def next_free_port( port=1024, max_port=65535 ):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
while port <= max_port:
try:
sock.bind(('', port))
sock.close()
return port
except OSError:
port += 1
raise IOError('no free ports')
def start_dashboard():
# pass optional second parameter "max_port" here, else scan until a free one is found
port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )
dashboard.configure(port=port)
dashboard.launch()
You can use netcat to make ports in-use for testing: nc -l -p 9999
will listen on port 9999; press control-C to end it.
$endgroup$
Your code has some incorrect assumptions.
an application may listen on a specific address/port combination;
127.0.0.1:port
can be available while*:port
is not.an application may bind a port without listening. Connects will fail, but so will your own bind.
a firewall or other mechanism can interfere with connections, generating false positives in your scan.
The reliable approach is to bind the port, just as your dashboard will, and then release it.
result = sock.bind(('', port))
sock.close()
You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard
logic cleaner and get rid of boolean loop-terminator scan_ports
. Just exit the loop by return
ing the answer.
def next_free_port( port=1024, max_port=65535 ):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
while port <= max_port:
try:
sock.bind(('', port))
sock.close()
return port
except OSError:
port += 1
raise IOError('no free ports')
def start_dashboard():
# pass optional second parameter "max_port" here, else scan until a free one is found
port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )
dashboard.configure(port=port)
dashboard.launch()
You can use netcat to make ports in-use for testing: nc -l -p 9999
will listen on port 9999; press control-C to end it.
edited 19 hours ago
answered yesterday
Oh My GoodnessOh My Goodness
1,799314
1,799314
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
1
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
1
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
|
show 1 more comment
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
1
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
1
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
Thank you for the answer, check is local, so no firewall in place.
$endgroup$
– spicyramen
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
I mean a host firewall, like iptables on Linux.
$endgroup$
– Oh My Goodness
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
$begingroup$
Sounds good, any recommendation for Python style? Thanks
$endgroup$
– spicyramen
yesterday
1
1
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
$begingroup$
the code can be a little shorter and clearer; see edits for a fleshed-out example.
$endgroup$
– Oh My Goodness
20 hours ago
1
1
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
$begingroup$
Thank you! Great sample
$endgroup$
– spicyramen
18 hours ago
|
show 1 more comment
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