Python scanner for the first free port in a rangePython Port ScannerPython Port Scanner 2.0Python Port Scanner 2.1Simple C Port ScannerIP Range Port ScannerIP Scanner via python socketsPython proxy checker/scannerThe start of a Python port scannerPython port scanner using multithreadingSimple port scanner in Python 3

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Python scanner for the first free port in a range


Python Port ScannerPython Port Scanner 2.0Python Port Scanner 2.1Simple C Port ScannerIP Range Port ScannerIP Scanner via python socketsPython proxy checker/scannerThe start of a Python port scannerPython port scanner using multithreadingSimple port scanner in Python 3













6












$begingroup$


I have a distributed application (YARN), which runs a WebApp.



This application use a default port to start (8008), before I start I need to check if port is in use.



A container may run in the same virtual machine, hence port may be in use.
(Max I have 4 containers in WebApp).



I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



def port_in_use(port):
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
result = sock.connect_ex(('127.0.0.1', port))
if result == 0:
return True
else:
return False


def start_dashboard():
base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
scan_ports = True
attempts = 0
max_attempts = 10
while(scan_ports and attempts <= max_attempts):
if port_in_use(base_port):
base_port += 1
attempts += 1
else:
scan_ports = False
if attempts == max_attempts:
raise IOError('Port in use')
dashboard.configure(port=base_port)
dashboard.launch()









share|improve this question











$endgroup$
















    6












    $begingroup$


    I have a distributed application (YARN), which runs a WebApp.



    This application use a default port to start (8008), before I start I need to check if port is in use.



    A container may run in the same virtual machine, hence port may be in use.
    (Max I have 4 containers in WebApp).



    I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



    def port_in_use(port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    result = sock.connect_ex(('127.0.0.1', port))
    if result == 0:
    return True
    else:
    return False


    def start_dashboard():
    base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
    scan_ports = True
    attempts = 0
    max_attempts = 10
    while(scan_ports and attempts <= max_attempts):
    if port_in_use(base_port):
    base_port += 1
    attempts += 1
    else:
    scan_ports = False
    if attempts == max_attempts:
    raise IOError('Port in use')
    dashboard.configure(port=base_port)
    dashboard.launch()









    share|improve this question











    $endgroup$














      6












      6








      6


      1



      $begingroup$


      I have a distributed application (YARN), which runs a WebApp.



      This application use a default port to start (8008), before I start I need to check if port is in use.



      A container may run in the same virtual machine, hence port may be in use.
      (Max I have 4 containers in WebApp).



      I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



      def port_in_use(port):
      sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
      result = sock.connect_ex(('127.0.0.1', port))
      if result == 0:
      return True
      else:
      return False


      def start_dashboard():
      base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
      scan_ports = True
      attempts = 0
      max_attempts = 10
      while(scan_ports and attempts <= max_attempts):
      if port_in_use(base_port):
      base_port += 1
      attempts += 1
      else:
      scan_ports = False
      if attempts == max_attempts:
      raise IOError('Port in use')
      dashboard.configure(port=base_port)
      dashboard.launch()









      share|improve this question











      $endgroup$




      I have a distributed application (YARN), which runs a WebApp.



      This application use a default port to start (8008), before I start I need to check if port is in use.



      A container may run in the same virtual machine, hence port may be in use.
      (Max I have 4 containers in WebApp).



      I created the following code which seem to work, but want to see if there are some clean ups/improvements suggested.



      def port_in_use(port):
      sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
      result = sock.connect_ex(('127.0.0.1', port))
      if result == 0:
      return True
      else:
      return False


      def start_dashboard():
      base_port = os.getenv('DASHBOARD_PORT_ENV_VAR', 8008)
      scan_ports = True
      attempts = 0
      max_attempts = 10
      while(scan_ports and attempts <= max_attempts):
      if port_in_use(base_port):
      base_port += 1
      attempts += 1
      else:
      scan_ports = False
      if attempts == max_attempts:
      raise IOError('Port in use')
      dashboard.configure(port=base_port)
      dashboard.launch()






      python python-3.x networking socket






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited yesterday









      200_success

      130k17155419




      130k17155419










      asked yesterday









      spicyramenspicyramen

      307312




      307312




















          1 Answer
          1






          active

          oldest

          votes


















          8












          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            yesterday










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            yesterday











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            yesterday






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            20 hours ago






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            18 hours ago










          Your Answer





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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          8












          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            yesterday










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            yesterday











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            yesterday






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            20 hours ago






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            18 hours ago















          8












          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$












          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            yesterday










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            yesterday











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            yesterday






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            20 hours ago






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            18 hours ago













          8












          8








          8





          $begingroup$

          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.






          share|improve this answer











          $endgroup$



          Your code has some incorrect assumptions.



          • an application may listen on a specific address/port combination; 127.0.0.1:port can be available while *:port is not.


          • an application may bind a port without listening. Connects will fail, but so will your own bind.


          • a firewall or other mechanism can interfere with connections, generating false positives in your scan.


          The reliable approach is to bind the port, just as your dashboard will, and then release it.



          result = sock.bind(('', port))
          sock.close()



          You'll need to catch the exception and this is a good opportunity to move the whole thing into a function. That will make the start_dashboard logic cleaner and get rid of boolean loop-terminator scan_ports. Just exit the loop by returning the answer.



          def next_free_port( port=1024, max_port=65535 ):
          sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
          while port <= max_port:
          try:
          sock.bind(('', port))
          sock.close()
          return port
          except OSError:
          port += 1
          raise IOError('no free ports')

          def start_dashboard():

          # pass optional second parameter "max_port" here, else scan until a free one is found
          port = next_free_port( os.getenv('DASHBOARD_PORT_ENV_VAR', 8008) )

          dashboard.configure(port=port)
          dashboard.launch()


          You can use netcat to make ports in-use for testing: nc -l -p 9999 will listen on port 9999; press control-C to end it.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 19 hours ago

























          answered yesterday









          Oh My GoodnessOh My Goodness

          1,799314




          1,799314











          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            yesterday










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            yesterday











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            yesterday






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            20 hours ago






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            18 hours ago
















          • $begingroup$
            Thank you for the answer, check is local, so no firewall in place.
            $endgroup$
            – spicyramen
            yesterday










          • $begingroup$
            I mean a host firewall, like iptables on Linux.
            $endgroup$
            – Oh My Goodness
            yesterday











          • $begingroup$
            Sounds good, any recommendation for Python style? Thanks
            $endgroup$
            – spicyramen
            yesterday






          • 1




            $begingroup$
            the code can be a little shorter and clearer; see edits for a fleshed-out example.
            $endgroup$
            – Oh My Goodness
            20 hours ago






          • 1




            $begingroup$
            Thank you! Great sample
            $endgroup$
            – spicyramen
            18 hours ago















          $begingroup$
          Thank you for the answer, check is local, so no firewall in place.
          $endgroup$
          – spicyramen
          yesterday




          $begingroup$
          Thank you for the answer, check is local, so no firewall in place.
          $endgroup$
          – spicyramen
          yesterday












          $begingroup$
          I mean a host firewall, like iptables on Linux.
          $endgroup$
          – Oh My Goodness
          yesterday





          $begingroup$
          I mean a host firewall, like iptables on Linux.
          $endgroup$
          – Oh My Goodness
          yesterday













          $begingroup$
          Sounds good, any recommendation for Python style? Thanks
          $endgroup$
          – spicyramen
          yesterday




          $begingroup$
          Sounds good, any recommendation for Python style? Thanks
          $endgroup$
          – spicyramen
          yesterday




          1




          1




          $begingroup$
          the code can be a little shorter and clearer; see edits for a fleshed-out example.
          $endgroup$
          – Oh My Goodness
          20 hours ago




          $begingroup$
          the code can be a little shorter and clearer; see edits for a fleshed-out example.
          $endgroup$
          – Oh My Goodness
          20 hours ago




          1




          1




          $begingroup$
          Thank you! Great sample
          $endgroup$
          – spicyramen
          18 hours ago




          $begingroup$
          Thank you! Great sample
          $endgroup$
          – spicyramen
          18 hours ago

















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