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how to capture specific strings from line
The 2019 Stack Overflow Developer Survey Results Are InReordering strings in linuxhow to delete line from the XML filelinux + how to capture values from xml fileawk + count field separator in csv and print line numberawk + how to capture email address between characterslinux + how to find the unused disk on linuxcapture the second field and the last field from stringawk/sed/perl one liner to edit json fileHow to insert file content after a certain string in a file?How to append line with strings at the end of variable?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
1
How to capture only the sdX from the following line using bash, awk, sed or perl in one liner command?
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","
expected output
sdb
sdc
sdd
sde
sdf
awk sed perl
edited 2 days ago
Prabhjot Singh
107213
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
add a comment |
1
How to capture only the sdX from the following line using bash, awk, sed or perl in one liner command?
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","
expected output
sdb
sdc
sdd
sde
sdf
awk sed perl
edited 2 days ago
Prabhjot Singh
107213
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
You can get that output withprintf '%sn' sdb sdc sdd sde sdf. If you want a more general answer, please explain what you want, in general. Do you want to extract thesdgfrom/dev/sdg, or only after/rid/? What if the input containssd1,sd17, orsda17? How aboutopen("/dev/sd#"); would you wantsd#(i.e., including the next character aftersd, even if it’s not alphanumeric)? How about words like “disdain”, “wisdom”, “eavesdrop”, “transduce”, “jurisdiction”, “misdeed”, “Tuesday”, “Wednesday” and “Thursday” (which contain “sd”)? How about “freebsd” (which ends with “sd”)?
– G-Man
Apr 6 at 15:56
This looks like it could be from a JSON file. Are you able to share a larger portion of the file?
– Kusalananda♦
2 days ago
add a comment |
1
1
1
How to capture only the sdX from the following line using bash, awk, sed or perl in one liner command?
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","
expected output
sdb
sdc
sdd
sde
sdf
awk sed perl
edited 2 days ago
Prabhjot Singh
107213
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
How to capture only the sdX from the following line using bash, awk, sed or perl in one liner command?
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","
expected output
sdb
sdc
sdd
sde
sdf
awk sed perl
awk sed perl
edited 2 days ago
Prabhjot Singh
107213
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
edited 2 days ago
Prabhjot Singh
107213
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
edited 2 days ago
Prabhjot Singh
107213
edited 2 days ago
Prabhjot Singh
107213
edited 2 days ago
Prabhjot Singh
107213
107213
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
asked Dec 22 '17 at 9:48
yaelyael
2,81243079
2,81243079
You can get that output withprintf '%sn' sdb sdc sdd sde sdf. If you want a more general answer, please explain what you want, in general. Do you want to extract thesdgfrom/dev/sdg, or only after/rid/? What if the input containssd1,sd17, orsda17? How aboutopen("/dev/sd#"); would you wantsd#(i.e., including the next character aftersd, even if it’s not alphanumeric)? How about words like “disdain”, “wisdom”, “eavesdrop”, “transduce”, “jurisdiction”, “misdeed”, “Tuesday”, “Wednesday” and “Thursday” (which contain “sd”)? How about “freebsd” (which ends with “sd”)?
– G-Man
Apr 6 at 15:56
This looks like it could be from a JSON file. Are you able to share a larger portion of the file?
– Kusalananda♦
2 days ago
add a comment |
You can get that output withprintf '%sn' sdb sdc sdd sde sdf. If you want a more general answer, please explain what you want, in general. Do you want to extract thesdgfrom/dev/sdg, or only after/rid/? What if the input containssd1,sd17, orsda17? How aboutopen("/dev/sd#"); would you wantsd#(i.e., including the next character aftersd, even if it’s not alphanumeric)? How about words like “disdain”, “wisdom”, “eavesdrop”, “transduce”, “jurisdiction”, “misdeed”, “Tuesday”, “Wednesday” and “Thursday” (which contain “sd”)? How about “freebsd” (which ends with “sd”)?
– G-Man
Apr 6 at 15:56
This looks like it could be from a JSON file. Are you able to share a larger portion of the file?
– Kusalananda♦
2 days ago
You can get that output with
printf '%sn' sdb sdc sdd sde sdf. If you want a more general answer, please explain what you want, in general. Do you want to extract the sdg from /dev/sdg, or only after /rid/? What if the input contains sd1, sd17, or sda17? How about open("/dev/sd#"); would you want sd# (i.e., including the next character after sd, even if it’s not alphanumeric)? How about words like “disdain”, “wisdom”, “eavesdrop”, “transduce”, “jurisdiction”, “misdeed”, “Tuesday”, “Wednesday” and “Thursday” (which contain “sd”)? How about “freebsd” (which ends with “sd”)?– G-Man
Apr 6 at 15:56
You can get that output with
printf '%sn' sdb sdc sdd sde sdf. If you want a more general answer, please explain what you want, in general. Do you want to extract the sdg from /dev/sdg, or only after /rid/? What if the input contains sd1, sd17, or sda17? How about open("/dev/sd#"); would you want sd# (i.e., including the next character after sd, even if it’s not alphanumeric)? How about words like “disdain”, “wisdom”, “eavesdrop”, “transduce”, “jurisdiction”, “misdeed”, “Tuesday”, “Wednesday” and “Thursday” (which contain “sd”)? How about “freebsd” (which ends with “sd”)?– G-Man
Apr 6 at 15:56
This looks like it could be from a JSON file. Are you able to share a larger portion of the file?
– Kusalananda♦
2 days ago
This looks like it could be from a JSON file. Are you able to share a larger portion of the file?
– Kusalananda♦
2 days ago
add a comment |
6 Answers
6
active
oldest
votes
2
You can use GREP arguments:
-P, --perl-regexp
Interpret the pattern as a Perl-compatible regular expression
(PCRE). This is experimental and grep -P may warn of
unimplemented features.
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
So your command would be:
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | grep -oP "w*sdw*"
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
1
Sorry, you talk about the option-Pand the you use-hto hide the filename?grepis (in this case) reading fromstdin
– FaxMax
Dec 22 '17 at 10:48
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
add a comment |
1
Use
echo ... | grep -Eo "sd[a-z]"
where -E interprets the pattern as an (extended) regular expression and -o prints only the matching parts in each line.
answered Dec 22 '17 at 10:48
elmelm
1134
1
That’s not an extended regular expression; that command will work without theEoption.
– G-Man
Apr 6 at 14:29
add a comment |
0
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",' | grep -Po 'sdw'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
add a comment |
0
You did not specify what x should be in sdX so one could as well assume that it might be any character:
$ echo echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs /data"," | grep -o 'sd.'
sdb
sdc
sdd
sde
sdf
A literal . means any character in regular expressions.
And in perl because you wanted that explicitly:
$ echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | perl -nE 'say $& while /sd./g'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
add a comment |
0
gnu sed:
$ s='"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
$ echo $s| sed -E ':b;s~[^,:]+.,3/rid/(.+)~1~;Te;h;s~(w+)/.*~1~p;g;tb;:e d'
answered Apr 6 at 13:35
abdanabdan
474
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So doesprintf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)
– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
add a comment |
0
Above result is achieved by awk one liner
Done by below command
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
output
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
sdb
sdc
sdd
sde
sdf
praveen@praveen:~$
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
add a comment |
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6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You can use GREP arguments:
-P, --perl-regexp
Interpret the pattern as a Perl-compatible regular expression
(PCRE). This is experimental and grep -P may warn of
unimplemented features.
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
So your command would be:
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | grep -oP "w*sdw*"
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
1
Sorry, you talk about the option-Pand the you use-hto hide the filename?grepis (in this case) reading fromstdin
– FaxMax
Dec 22 '17 at 10:48
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
add a comment |
2
You can use GREP arguments:
-P, --perl-regexp
Interpret the pattern as a Perl-compatible regular expression
(PCRE). This is experimental and grep -P may warn of
unimplemented features.
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
So your command would be:
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | grep -oP "w*sdw*"
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
1
Sorry, you talk about the option-Pand the you use-hto hide the filename?grepis (in this case) reading fromstdin
– FaxMax
Dec 22 '17 at 10:48
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
add a comment |
2
2
2
You can use GREP arguments:
-P, --perl-regexp
Interpret the pattern as a Perl-compatible regular expression
(PCRE). This is experimental and grep -P may warn of
unimplemented features.
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
So your command would be:
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | grep -oP "w*sdw*"
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
You can use GREP arguments:
-P, --perl-regexp
Interpret the pattern as a Perl-compatible regular expression
(PCRE). This is experimental and grep -P may warn of
unimplemented features.
-o, --only-matching
Print only the matched (non-empty) parts of a matching line,
with each such part on a separate output line.
So your command would be:
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | grep -oP "w*sdw*"
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
edited Dec 22 '17 at 11:04
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
answered Dec 22 '17 at 10:41
Kevin LemaireKevin Lemaire
1,181724
1,181724
1
Sorry, you talk about the option-Pand the you use-hto hide the filename?grepis (in this case) reading fromstdin
– FaxMax
Dec 22 '17 at 10:48
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
add a comment |
1
Sorry, you talk about the option-Pand the you use-hto hide the filename?grepis (in this case) reading fromstdin
– FaxMax
Dec 22 '17 at 10:48
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
1
1
Sorry, you talk about the option
-P and the you use -h to hide the filename? grep is (in this case) reading from stdin– FaxMax
Dec 22 '17 at 10:48
Sorry, you talk about the option
-P and the you use -h to hide the filename? grep is (in this case) reading from stdin– FaxMax
Dec 22 '17 at 10:48
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
Corrected, wrong copy/paste. Thanks.
– Kevin Lemaire
Dec 22 '17 at 10:52
add a comment |
1
Use
echo ... | grep -Eo "sd[a-z]"
where -E interprets the pattern as an (extended) regular expression and -o prints only the matching parts in each line.
answered Dec 22 '17 at 10:48
elmelm
1134
1
That’s not an extended regular expression; that command will work without theEoption.
– G-Man
Apr 6 at 14:29
add a comment |
1
Use
echo ... | grep -Eo "sd[a-z]"
where -E interprets the pattern as an (extended) regular expression and -o prints only the matching parts in each line.
answered Dec 22 '17 at 10:48
elmelm
1134
1
That’s not an extended regular expression; that command will work without theEoption.
– G-Man
Apr 6 at 14:29
add a comment |
1
1
1
Use
echo ... | grep -Eo "sd[a-z]"
where -E interprets the pattern as an (extended) regular expression and -o prints only the matching parts in each line.
answered Dec 22 '17 at 10:48
elmelm
1134
Use
echo ... | grep -Eo "sd[a-z]"
where -E interprets the pattern as an (extended) regular expression and -o prints only the matching parts in each line.
answered Dec 22 '17 at 10:48
elmelm
1134
answered Dec 22 '17 at 10:48
elmelm
1134
answered Dec 22 '17 at 10:48
elmelm
1134
answered Dec 22 '17 at 10:48
elmelm
1134
1134
1
That’s not an extended regular expression; that command will work without theEoption.
– G-Man
Apr 6 at 14:29
add a comment |
1
That’s not an extended regular expression; that command will work without theEoption.
– G-Man
Apr 6 at 14:29
1
1
That’s not an extended regular expression; that command will work without the
E option.– G-Man
Apr 6 at 14:29
That’s not an extended regular expression; that command will work without the
E option.– G-Man
Apr 6 at 14:29
add a comment |
0
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",' | grep -Po 'sdw'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
add a comment |
0
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",' | grep -Po 'sdw'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
add a comment |
0
0
0
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",' | grep -Po 'sdw'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",
echo '"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",' | grep -Po 'sdw'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
answered Dec 22 '17 at 10:37
FaxMaxFaxMax
443420
443420
add a comment |
add a comment |
0
You did not specify what x should be in sdX so one could as well assume that it might be any character:
$ echo echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs /data"," | grep -o 'sd.'
sdb
sdc
sdd
sde
sdf
A literal . means any character in regular expressions.
And in perl because you wanted that explicitly:
$ echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | perl -nE 'say $& while /sd./g'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
add a comment |
0
You did not specify what x should be in sdX so one could as well assume that it might be any character:
$ echo echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs /data"," | grep -o 'sd.'
sdb
sdc
sdd
sde
sdf
A literal . means any character in regular expressions.
And in perl because you wanted that explicitly:
$ echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | perl -nE 'say $& while /sd./g'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
add a comment |
0
0
0
You did not specify what x should be in sdX so one could as well assume that it might be any character:
$ echo echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs /data"," | grep -o 'sd.'
sdb
sdc
sdd
sde
sdf
A literal . means any character in regular expressions.
And in perl because you wanted that explicitly:
$ echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | perl -nE 'say $& while /sd./g'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
You did not specify what x should be in sdX so one could as well assume that it might be any character:
$ echo echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs /data"," | grep -o 'sd.'
sdb
sdc
sdd
sde
sdf
A literal . means any character in regular expressions.
And in perl because you wanted that explicitly:
$ echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data"," | perl -nE 'say $& while /sd./g'
sdb
sdc
sdd
sde
sdf
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
edited Dec 22 '17 at 12:15
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
answered Dec 22 '17 at 11:03
Arkadiusz DrabczykArkadiusz Drabczyk
8,33521836
8,33521836
add a comment |
add a comment |
0
gnu sed:
$ s='"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
$ echo $s| sed -E ':b;s~[^,:]+.,3/rid/(.+)~1~;Te;h;s~(w+)/.*~1~p;g;tb;:e d'
answered Apr 6 at 13:35
abdanabdan
474
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So doesprintf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)
– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
add a comment |
0
gnu sed:
$ s='"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
$ echo $s| sed -E ':b;s~[^,:]+.,3/rid/(.+)~1~;Te;h;s~(w+)/.*~1~p;g;tb;:e d'
answered Apr 6 at 13:35
abdanabdan
474
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So doesprintf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)
– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
add a comment |
0
0
0
gnu sed:
$ s='"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
$ echo $s| sed -E ':b;s~[^,:]+.,3/rid/(.+)~1~;Te;h;s~(w+)/.*~1~p;g;tb;:e d'
answered Apr 6 at 13:35
abdanabdan
474
gnu sed:
$ s='"dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data",'
$ echo $s| sed -E ':b;s~[^,:]+.,3/rid/(.+)~1~;Te;h;s~(w+)/.*~1~p;g;tb;:e d'
answered Apr 6 at 13:35
abdanabdan
474
answered Apr 6 at 13:35
abdanabdan
474
answered Apr 6 at 13:35
abdanabdan
474
answered Apr 6 at 13:35
abdanabdan
474
474
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So doesprintf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)
– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
add a comment |
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So doesprintf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)
– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
I do not get it
– Pierre.Vriens
Apr 6 at 13:55
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So does
printf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)– G-Man
Apr 6 at 15:28
(1) You might not be able to tell from the previous answers to this question, but we prefer answers to explain how they work — especially when they’re as complicated as this one, and when they are added to a long list of other answers, long after the question was asked. (2) Your command produces the correct expected result for the sample input. So does
printf '%sn' sdb sdc sdd sde sdf. Of course that wouldn’t be an acceptable answer; it would work only for the sample input, and essentially nothing else. … (Cont’d)– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
(Cont’d) … My point is that the same is true of your answer. The question says “capture only the sdX …”; you have made many assumptions about the input, in general, assuming that it will look very very much like the sample input. It is necessary to make some assumptions about what the questioner wants, because the question is terribly vague. But you should state what assumptions you are making, especially when they are as broad as the ones you are making.
– G-Man
Apr 6 at 15:28
add a comment |
0
Above result is achieved by awk one liner
Done by below command
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
output
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
sdb
sdc
sdd
sde
sdf
praveen@praveen:~$
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
add a comment |
0
Above result is achieved by awk one liner
Done by below command
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
output
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
sdb
sdc
sdd
sde
sdf
praveen@praveen:~$
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
add a comment |
0
0
0
Above result is achieved by awk one liner
Done by below command
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
output
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
sdb
sdc
sdd
sde
sdf
praveen@praveen:~$
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
Above result is achieved by awk one liner
Done by below command
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
output
echo ""dfs.datanode.data.dir" : "/rid/sdb/oo/hdfs/data,/rid/sdc/oo/hdfs/data,/rid/sdd/oo/hdfs/data,/rid/sde/oo/hdfs/data,/rid/sdf/oo/hdfs/data","|perl -pne "s/,/n/g"| sed '/^$/d'| awk -F "/" 'print $3'
sdb
sdc
sdd
sde
sdf
praveen@praveen:~$
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
answered 2 days ago
Praveen Kumar BSPraveen Kumar BS
1,7541311
1,7541311
add a comment |
add a comment |
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You can get that output with
printf '%sn' sdb sdc sdd sde sdf. If you want a more general answer, please explain what you want, in general. Do you want to extract thesdgfrom/dev/sdg, or only after/rid/? What if the input containssd1,sd17, orsda17? How aboutopen("/dev/sd#"); would you wantsd#(i.e., including the next character aftersd, even if it’s not alphanumeric)? How about words like “disdain”, “wisdom”, “eavesdrop”, “transduce”, “jurisdiction”, “misdeed”, “Tuesday”, “Wednesday” and “Thursday” (which contain “sd”)? How about “freebsd” (which ends with “sd”)?– G-Man
Apr 6 at 15:56
This looks like it could be from a JSON file. Are you able to share a larger portion of the file?
– Kusalananda♦
2 days ago