Use journalctl to show logs of specific unit which has a parameter?Where is / why is there no log for normal user systemd services?I can't enable or disable a user service: Failed to execute operation: No such file or directoryDoes journalctl give access to all logs?Reloading systemd-journald configHow to use systemd aliases with journalctl?Why journalctl outputs in ASCII?Why journalctl does not display log message if I use filtering by unit?Bypass systemd-journald to send messages directly to ryslog daemonSystemd service isn't restarted, no explanation of failureGetting systemd service logs faster from my service
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Use journalctl to show logs of specific unit which has a parameter?
Where is / why is there no log for normal user systemd services?I can't enable or disable a user service: Failed to execute operation: No such file or directoryDoes journalctl give access to all logs?Reloading systemd-journald configHow to use systemd aliases with journalctl?Why journalctl outputs in ASCII?Why journalctl does not display log message if I use filtering by unit?Bypass systemd-journald to send messages directly to ryslog daemonSystemd service isn't restarted, no explanation of failureGetting systemd service logs faster from my service
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have one systemd service which runs with systemctl --user start test_unit@random_arguments
. How could I use journalctl
to filter all logs of test_unit
? If it supports "follow mode", that's even better.
systemd systemd-journald journalctl
New contributor
add a comment |
I have one systemd service which runs with systemctl --user start test_unit@random_arguments
. How could I use journalctl
to filter all logs of test_unit
? If it supports "follow mode", that's even better.
systemd systemd-journald journalctl
New contributor
add a comment |
I have one systemd service which runs with systemctl --user start test_unit@random_arguments
. How could I use journalctl
to filter all logs of test_unit
? If it supports "follow mode", that's even better.
systemd systemd-journald journalctl
New contributor
I have one systemd service which runs with systemctl --user start test_unit@random_arguments
. How could I use journalctl
to filter all logs of test_unit
? If it supports "follow mode", that's even better.
systemd systemd-journald journalctl
systemd systemd-journald journalctl
New contributor
New contributor
edited 2 days ago
Guisong He
New contributor
asked 2 days ago
Guisong HeGuisong He
1034
1034
New contributor
New contributor
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
If this is a user unit, use the --user-unit
option:
journalctl -f --user-unit=test_unit@random_arguments
Otherwise, filter the unit with _SYSTEMD_UNIT
:
sudo journalctl -f _SYSTEMD_UNIT=test_unit@random_arguments
Thanks. The--user
option saves my day.journalctl --user -u test_unit@* -f
works
– Guisong He
2 days ago
1
Right,--user-unit
combines--user
and-u
;-).
– Stephen Kitt
2 days ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If this is a user unit, use the --user-unit
option:
journalctl -f --user-unit=test_unit@random_arguments
Otherwise, filter the unit with _SYSTEMD_UNIT
:
sudo journalctl -f _SYSTEMD_UNIT=test_unit@random_arguments
Thanks. The--user
option saves my day.journalctl --user -u test_unit@* -f
works
– Guisong He
2 days ago
1
Right,--user-unit
combines--user
and-u
;-).
– Stephen Kitt
2 days ago
add a comment |
If this is a user unit, use the --user-unit
option:
journalctl -f --user-unit=test_unit@random_arguments
Otherwise, filter the unit with _SYSTEMD_UNIT
:
sudo journalctl -f _SYSTEMD_UNIT=test_unit@random_arguments
Thanks. The--user
option saves my day.journalctl --user -u test_unit@* -f
works
– Guisong He
2 days ago
1
Right,--user-unit
combines--user
and-u
;-).
– Stephen Kitt
2 days ago
add a comment |
If this is a user unit, use the --user-unit
option:
journalctl -f --user-unit=test_unit@random_arguments
Otherwise, filter the unit with _SYSTEMD_UNIT
:
sudo journalctl -f _SYSTEMD_UNIT=test_unit@random_arguments
If this is a user unit, use the --user-unit
option:
journalctl -f --user-unit=test_unit@random_arguments
Otherwise, filter the unit with _SYSTEMD_UNIT
:
sudo journalctl -f _SYSTEMD_UNIT=test_unit@random_arguments
answered 2 days ago
Stephen KittStephen Kitt
180k25408486
180k25408486
Thanks. The--user
option saves my day.journalctl --user -u test_unit@* -f
works
– Guisong He
2 days ago
1
Right,--user-unit
combines--user
and-u
;-).
– Stephen Kitt
2 days ago
add a comment |
Thanks. The--user
option saves my day.journalctl --user -u test_unit@* -f
works
– Guisong He
2 days ago
1
Right,--user-unit
combines--user
and-u
;-).
– Stephen Kitt
2 days ago
Thanks. The
--user
option saves my day. journalctl --user -u test_unit@* -f
works– Guisong He
2 days ago
Thanks. The
--user
option saves my day. journalctl --user -u test_unit@* -f
works– Guisong He
2 days ago
1
1
Right,
--user-unit
combines --user
and -u
;-).– Stephen Kitt
2 days ago
Right,
--user-unit
combines --user
and -u
;-).– Stephen Kitt
2 days ago
add a comment |
Guisong He is a new contributor. Be nice, and check out our Code of Conduct.
Guisong He is a new contributor. Be nice, and check out our Code of Conduct.
Guisong He is a new contributor. Be nice, and check out our Code of Conduct.
Guisong He is a new contributor. Be nice, and check out our Code of Conduct.
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