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Bridge building with irregular planks


Fastest way to collect an arbitrary armyDo better than chanceGreatest Digital Clock Number, with a Twist!The Old Miss GruppeHow much water do you need to cross the desert?Create bridges to minimise distanceCovering Table with CoinsHow many different kinds of rings are there?Constructing 0.35 Unit LengthOptimal Money-Saving on the NYC Metro













3












$begingroup$


Imagine you have a big rectangular pond in your back garden. You wish to build a bridge from your house in the lower left corner to the small pagoda in the top right.



You have lots of planks of length $1$ and $2$. You only wish to place planks orthogonal to the sides of the pond, and you don't want to go backwards ever. The pond is $10times10$.




How many ways are there to do this?




For example:




. . . ._P
|
. . . . .
|
. . . . .
|
. . ._. .
|
H_._. . .



For a bonus, is there a generic solution for planks of length $l_1,l_2,dots,l_k$?











share|improve this question









$endgroup$
















    3












    $begingroup$


    Imagine you have a big rectangular pond in your back garden. You wish to build a bridge from your house in the lower left corner to the small pagoda in the top right.



    You have lots of planks of length $1$ and $2$. You only wish to place planks orthogonal to the sides of the pond, and you don't want to go backwards ever. The pond is $10times10$.




    How many ways are there to do this?




    For example:




    . . . ._P
    |
    . . . . .
    |
    . . . . .
    |
    . . ._. .
    |
    H_._. . .



    For a bonus, is there a generic solution for planks of length $l_1,l_2,dots,l_k$?











    share|improve this question









    $endgroup$














      3












      3








      3





      $begingroup$


      Imagine you have a big rectangular pond in your back garden. You wish to build a bridge from your house in the lower left corner to the small pagoda in the top right.



      You have lots of planks of length $1$ and $2$. You only wish to place planks orthogonal to the sides of the pond, and you don't want to go backwards ever. The pond is $10times10$.




      How many ways are there to do this?




      For example:




      . . . ._P
      |
      . . . . .
      |
      . . . . .
      |
      . . ._. .
      |
      H_._. . .



      For a bonus, is there a generic solution for planks of length $l_1,l_2,dots,l_k$?











      share|improve this question









      $endgroup$




      Imagine you have a big rectangular pond in your back garden. You wish to build a bridge from your house in the lower left corner to the small pagoda in the top right.



      You have lots of planks of length $1$ and $2$. You only wish to place planks orthogonal to the sides of the pond, and you don't want to go backwards ever. The pond is $10times10$.




      How many ways are there to do this?




      For example:




      . . . ._P
      |
      . . . . .
      |
      . . . . .
      |
      . . ._. .
      |
      H_._. . .



      For a bonus, is there a generic solution for planks of length $l_1,l_2,dots,l_k$?








      mathematics combinatorics






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked yesterday









      JonMark PerryJonMark Perry

      20.4k64099




      20.4k64099




















          2 Answers
          2






          active

          oldest

          votes


















          8












          $begingroup$

          Rather than thinking of planks as having lengths, think of them as defining certain sets of vectors. So in this case we have (1,0), (0,1), (2,0), (0,2). (Caution: if you have e.g. a plank of length 5 then you need to allow (3,4) and (4,3) as well as (5,0) and (0,5)! [EDITED to add:] No, as pointed out by another user in comments that's wrong because the question specifies orthogonal only. Though obviously you could also do it the other way if you wanted :-).)



          Now we have a recurrence relation: if we write $N(a,b)$ for the number of ways to span a pond of size $(a,b)$ then we have $N(0,0)=1$ and $N(a,b)=sum N(a-x,b-y)$ where the sum is over plank-vectors $(x,y)$.



          For the particular case here, the table looks like this:



          $$beginarrayr
          1 & 1 & 2 & 3 & 5 & 8 & 13 & 21 & 34 & 55 & 89 \
          1 & 2 & 5 & 10 & 20 & 38 & 71 & 130 & 235 & 420 & 744 \
          2 & 5 & 14 & 32 & 71 & 149 & 304 & 604 & 1177 & 2256 & 4266 \
          3 & 10 & 32 & 84 & 207 & 478 & 1060 & 2272 & 4744 & 9692 & 19446 \
          5 & 20 & 71 & 207 & 556 & 1390 & 3310 & 7576 & 16807 & 36331 & 76850 \
          8 & 38 & 149 & 478 & 1390 & 3736 & 9496 & 23080 & 54127 & 123230 & 273653 \
          13 & 71 & 304 & 1060 & 3310 & 9496 & 25612 & 65764 & 162310 & 387635 & 900448 \
          21 & 130 & 604 & 2272 & 7576 & 23080 & 65764 & 177688 & 459889 & 1148442 & 2782432 \
          34 & 235 & 1177 & 4744 & 16807 & 54127 & 162310 & 459889 & 1244398 & 3240364 & 8167642 \
          55 & 420 & 2256 & 9692 & 36331 & 123230 & 387635 & 1148442 & 3240364 & 8777612 & 22968050 \
          89 & 744 & 4266 & 19446 & 76850 & 273653 & 900448 & 2782432 & 8167642 & 22968050 & 62271384
          endarray
          $$



          The number you want is in the bottom right of the array. This happens to be http://oeis.org/A036355. In general, the generating function for these things is $frac11-sum x^dxy^dy$ where the sum is over plank-vectors $(dx,dy)$. I guess you can probably get a closed form out of that somehow.






          share|improve this answer











          $endgroup$








          • 2




            $begingroup$
            I was about to post the same table. :-)
            $endgroup$
            – Jaap Scherphuis
            yesterday






          • 1




            $begingroup$
            Why am I not surprised that the person saying that is you? :-)
            $endgroup$
            – Gareth McCaughan
            yesterday






          • 9




            $begingroup$
            On my computer, the table spills over into the HNQ. Maybe just me?
            $endgroup$
            – Brandon_J
            yesterday






          • 1




            $begingroup$
            @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
            $endgroup$
            – Billy Mailman
            yesterday






          • 1




            $begingroup$
            @Brandon_J Not just you, me too
            $endgroup$
            – Sensoray
            yesterday


















          2












          $begingroup$

          My answer (using a computer program) is:




          There are 8777612 ways to arrange the planks.

          I solved this using a C program


          #include <stdio.h>

          #define WIDTH 10
          #define DEPTH 10
          #define PLANK 2

          unsigned long long cache[DEPTH][WIDTH];

          unsigned long long recur(int row, int col)

          int main(void)
          printf("Paths = %llun", recur(0, 0));




          Note that this is from coordinate (0,0) to (9,9) because the start and finish points are in the pond. The distance is $9$ in each direction. It checks out when manually counting small ponds.



          This also provides a generic solution for ponds up to $26 times 26$, or up to $2^64-1$ paths.

          For small ponds the cache isn't necessary.






          share|improve this answer











          $endgroup$












          • $begingroup$
            @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
            $endgroup$
            – Weather Vane
            yesterday











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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          8












          $begingroup$

          Rather than thinking of planks as having lengths, think of them as defining certain sets of vectors. So in this case we have (1,0), (0,1), (2,0), (0,2). (Caution: if you have e.g. a plank of length 5 then you need to allow (3,4) and (4,3) as well as (5,0) and (0,5)! [EDITED to add:] No, as pointed out by another user in comments that's wrong because the question specifies orthogonal only. Though obviously you could also do it the other way if you wanted :-).)



          Now we have a recurrence relation: if we write $N(a,b)$ for the number of ways to span a pond of size $(a,b)$ then we have $N(0,0)=1$ and $N(a,b)=sum N(a-x,b-y)$ where the sum is over plank-vectors $(x,y)$.



          For the particular case here, the table looks like this:



          $$beginarrayr
          1 & 1 & 2 & 3 & 5 & 8 & 13 & 21 & 34 & 55 & 89 \
          1 & 2 & 5 & 10 & 20 & 38 & 71 & 130 & 235 & 420 & 744 \
          2 & 5 & 14 & 32 & 71 & 149 & 304 & 604 & 1177 & 2256 & 4266 \
          3 & 10 & 32 & 84 & 207 & 478 & 1060 & 2272 & 4744 & 9692 & 19446 \
          5 & 20 & 71 & 207 & 556 & 1390 & 3310 & 7576 & 16807 & 36331 & 76850 \
          8 & 38 & 149 & 478 & 1390 & 3736 & 9496 & 23080 & 54127 & 123230 & 273653 \
          13 & 71 & 304 & 1060 & 3310 & 9496 & 25612 & 65764 & 162310 & 387635 & 900448 \
          21 & 130 & 604 & 2272 & 7576 & 23080 & 65764 & 177688 & 459889 & 1148442 & 2782432 \
          34 & 235 & 1177 & 4744 & 16807 & 54127 & 162310 & 459889 & 1244398 & 3240364 & 8167642 \
          55 & 420 & 2256 & 9692 & 36331 & 123230 & 387635 & 1148442 & 3240364 & 8777612 & 22968050 \
          89 & 744 & 4266 & 19446 & 76850 & 273653 & 900448 & 2782432 & 8167642 & 22968050 & 62271384
          endarray
          $$



          The number you want is in the bottom right of the array. This happens to be http://oeis.org/A036355. In general, the generating function for these things is $frac11-sum x^dxy^dy$ where the sum is over plank-vectors $(dx,dy)$. I guess you can probably get a closed form out of that somehow.






          share|improve this answer











          $endgroup$








          • 2




            $begingroup$
            I was about to post the same table. :-)
            $endgroup$
            – Jaap Scherphuis
            yesterday






          • 1




            $begingroup$
            Why am I not surprised that the person saying that is you? :-)
            $endgroup$
            – Gareth McCaughan
            yesterday






          • 9




            $begingroup$
            On my computer, the table spills over into the HNQ. Maybe just me?
            $endgroup$
            – Brandon_J
            yesterday






          • 1




            $begingroup$
            @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
            $endgroup$
            – Billy Mailman
            yesterday






          • 1




            $begingroup$
            @Brandon_J Not just you, me too
            $endgroup$
            – Sensoray
            yesterday















          8












          $begingroup$

          Rather than thinking of planks as having lengths, think of them as defining certain sets of vectors. So in this case we have (1,0), (0,1), (2,0), (0,2). (Caution: if you have e.g. a plank of length 5 then you need to allow (3,4) and (4,3) as well as (5,0) and (0,5)! [EDITED to add:] No, as pointed out by another user in comments that's wrong because the question specifies orthogonal only. Though obviously you could also do it the other way if you wanted :-).)



          Now we have a recurrence relation: if we write $N(a,b)$ for the number of ways to span a pond of size $(a,b)$ then we have $N(0,0)=1$ and $N(a,b)=sum N(a-x,b-y)$ where the sum is over plank-vectors $(x,y)$.



          For the particular case here, the table looks like this:



          $$beginarrayr
          1 & 1 & 2 & 3 & 5 & 8 & 13 & 21 & 34 & 55 & 89 \
          1 & 2 & 5 & 10 & 20 & 38 & 71 & 130 & 235 & 420 & 744 \
          2 & 5 & 14 & 32 & 71 & 149 & 304 & 604 & 1177 & 2256 & 4266 \
          3 & 10 & 32 & 84 & 207 & 478 & 1060 & 2272 & 4744 & 9692 & 19446 \
          5 & 20 & 71 & 207 & 556 & 1390 & 3310 & 7576 & 16807 & 36331 & 76850 \
          8 & 38 & 149 & 478 & 1390 & 3736 & 9496 & 23080 & 54127 & 123230 & 273653 \
          13 & 71 & 304 & 1060 & 3310 & 9496 & 25612 & 65764 & 162310 & 387635 & 900448 \
          21 & 130 & 604 & 2272 & 7576 & 23080 & 65764 & 177688 & 459889 & 1148442 & 2782432 \
          34 & 235 & 1177 & 4744 & 16807 & 54127 & 162310 & 459889 & 1244398 & 3240364 & 8167642 \
          55 & 420 & 2256 & 9692 & 36331 & 123230 & 387635 & 1148442 & 3240364 & 8777612 & 22968050 \
          89 & 744 & 4266 & 19446 & 76850 & 273653 & 900448 & 2782432 & 8167642 & 22968050 & 62271384
          endarray
          $$



          The number you want is in the bottom right of the array. This happens to be http://oeis.org/A036355. In general, the generating function for these things is $frac11-sum x^dxy^dy$ where the sum is over plank-vectors $(dx,dy)$. I guess you can probably get a closed form out of that somehow.






          share|improve this answer











          $endgroup$








          • 2




            $begingroup$
            I was about to post the same table. :-)
            $endgroup$
            – Jaap Scherphuis
            yesterday






          • 1




            $begingroup$
            Why am I not surprised that the person saying that is you? :-)
            $endgroup$
            – Gareth McCaughan
            yesterday






          • 9




            $begingroup$
            On my computer, the table spills over into the HNQ. Maybe just me?
            $endgroup$
            – Brandon_J
            yesterday






          • 1




            $begingroup$
            @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
            $endgroup$
            – Billy Mailman
            yesterday






          • 1




            $begingroup$
            @Brandon_J Not just you, me too
            $endgroup$
            – Sensoray
            yesterday













          8












          8








          8





          $begingroup$

          Rather than thinking of planks as having lengths, think of them as defining certain sets of vectors. So in this case we have (1,0), (0,1), (2,0), (0,2). (Caution: if you have e.g. a plank of length 5 then you need to allow (3,4) and (4,3) as well as (5,0) and (0,5)! [EDITED to add:] No, as pointed out by another user in comments that's wrong because the question specifies orthogonal only. Though obviously you could also do it the other way if you wanted :-).)



          Now we have a recurrence relation: if we write $N(a,b)$ for the number of ways to span a pond of size $(a,b)$ then we have $N(0,0)=1$ and $N(a,b)=sum N(a-x,b-y)$ where the sum is over plank-vectors $(x,y)$.



          For the particular case here, the table looks like this:



          $$beginarrayr
          1 & 1 & 2 & 3 & 5 & 8 & 13 & 21 & 34 & 55 & 89 \
          1 & 2 & 5 & 10 & 20 & 38 & 71 & 130 & 235 & 420 & 744 \
          2 & 5 & 14 & 32 & 71 & 149 & 304 & 604 & 1177 & 2256 & 4266 \
          3 & 10 & 32 & 84 & 207 & 478 & 1060 & 2272 & 4744 & 9692 & 19446 \
          5 & 20 & 71 & 207 & 556 & 1390 & 3310 & 7576 & 16807 & 36331 & 76850 \
          8 & 38 & 149 & 478 & 1390 & 3736 & 9496 & 23080 & 54127 & 123230 & 273653 \
          13 & 71 & 304 & 1060 & 3310 & 9496 & 25612 & 65764 & 162310 & 387635 & 900448 \
          21 & 130 & 604 & 2272 & 7576 & 23080 & 65764 & 177688 & 459889 & 1148442 & 2782432 \
          34 & 235 & 1177 & 4744 & 16807 & 54127 & 162310 & 459889 & 1244398 & 3240364 & 8167642 \
          55 & 420 & 2256 & 9692 & 36331 & 123230 & 387635 & 1148442 & 3240364 & 8777612 & 22968050 \
          89 & 744 & 4266 & 19446 & 76850 & 273653 & 900448 & 2782432 & 8167642 & 22968050 & 62271384
          endarray
          $$



          The number you want is in the bottom right of the array. This happens to be http://oeis.org/A036355. In general, the generating function for these things is $frac11-sum x^dxy^dy$ where the sum is over plank-vectors $(dx,dy)$. I guess you can probably get a closed form out of that somehow.






          share|improve this answer











          $endgroup$



          Rather than thinking of planks as having lengths, think of them as defining certain sets of vectors. So in this case we have (1,0), (0,1), (2,0), (0,2). (Caution: if you have e.g. a plank of length 5 then you need to allow (3,4) and (4,3) as well as (5,0) and (0,5)! [EDITED to add:] No, as pointed out by another user in comments that's wrong because the question specifies orthogonal only. Though obviously you could also do it the other way if you wanted :-).)



          Now we have a recurrence relation: if we write $N(a,b)$ for the number of ways to span a pond of size $(a,b)$ then we have $N(0,0)=1$ and $N(a,b)=sum N(a-x,b-y)$ where the sum is over plank-vectors $(x,y)$.



          For the particular case here, the table looks like this:



          $$beginarrayr
          1 & 1 & 2 & 3 & 5 & 8 & 13 & 21 & 34 & 55 & 89 \
          1 & 2 & 5 & 10 & 20 & 38 & 71 & 130 & 235 & 420 & 744 \
          2 & 5 & 14 & 32 & 71 & 149 & 304 & 604 & 1177 & 2256 & 4266 \
          3 & 10 & 32 & 84 & 207 & 478 & 1060 & 2272 & 4744 & 9692 & 19446 \
          5 & 20 & 71 & 207 & 556 & 1390 & 3310 & 7576 & 16807 & 36331 & 76850 \
          8 & 38 & 149 & 478 & 1390 & 3736 & 9496 & 23080 & 54127 & 123230 & 273653 \
          13 & 71 & 304 & 1060 & 3310 & 9496 & 25612 & 65764 & 162310 & 387635 & 900448 \
          21 & 130 & 604 & 2272 & 7576 & 23080 & 65764 & 177688 & 459889 & 1148442 & 2782432 \
          34 & 235 & 1177 & 4744 & 16807 & 54127 & 162310 & 459889 & 1244398 & 3240364 & 8167642 \
          55 & 420 & 2256 & 9692 & 36331 & 123230 & 387635 & 1148442 & 3240364 & 8777612 & 22968050 \
          89 & 744 & 4266 & 19446 & 76850 & 273653 & 900448 & 2782432 & 8167642 & 22968050 & 62271384
          endarray
          $$



          The number you want is in the bottom right of the array. This happens to be http://oeis.org/A036355. In general, the generating function for these things is $frac11-sum x^dxy^dy$ where the sum is over plank-vectors $(dx,dy)$. I guess you can probably get a closed form out of that somehow.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited yesterday

























          answered yesterday









          Gareth McCaughanGareth McCaughan

          65k3164254




          65k3164254







          • 2




            $begingroup$
            I was about to post the same table. :-)
            $endgroup$
            – Jaap Scherphuis
            yesterday






          • 1




            $begingroup$
            Why am I not surprised that the person saying that is you? :-)
            $endgroup$
            – Gareth McCaughan
            yesterday






          • 9




            $begingroup$
            On my computer, the table spills over into the HNQ. Maybe just me?
            $endgroup$
            – Brandon_J
            yesterday






          • 1




            $begingroup$
            @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
            $endgroup$
            – Billy Mailman
            yesterday






          • 1




            $begingroup$
            @Brandon_J Not just you, me too
            $endgroup$
            – Sensoray
            yesterday












          • 2




            $begingroup$
            I was about to post the same table. :-)
            $endgroup$
            – Jaap Scherphuis
            yesterday






          • 1




            $begingroup$
            Why am I not surprised that the person saying that is you? :-)
            $endgroup$
            – Gareth McCaughan
            yesterday






          • 9




            $begingroup$
            On my computer, the table spills over into the HNQ. Maybe just me?
            $endgroup$
            – Brandon_J
            yesterday






          • 1




            $begingroup$
            @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
            $endgroup$
            – Billy Mailman
            yesterday






          • 1




            $begingroup$
            @Brandon_J Not just you, me too
            $endgroup$
            – Sensoray
            yesterday







          2




          2




          $begingroup$
          I was about to post the same table. :-)
          $endgroup$
          – Jaap Scherphuis
          yesterday




          $begingroup$
          I was about to post the same table. :-)
          $endgroup$
          – Jaap Scherphuis
          yesterday




          1




          1




          $begingroup$
          Why am I not surprised that the person saying that is you? :-)
          $endgroup$
          – Gareth McCaughan
          yesterday




          $begingroup$
          Why am I not surprised that the person saying that is you? :-)
          $endgroup$
          – Gareth McCaughan
          yesterday




          9




          9




          $begingroup$
          On my computer, the table spills over into the HNQ. Maybe just me?
          $endgroup$
          – Brandon_J
          yesterday




          $begingroup$
          On my computer, the table spills over into the HNQ. Maybe just me?
          $endgroup$
          – Brandon_J
          yesterday




          1




          1




          $begingroup$
          @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
          $endgroup$
          – Billy Mailman
          yesterday




          $begingroup$
          @GarethMcCaughan The (3,4)/(4,3) bit is wrong, and confused me for a minute before I realized what you meant. You can't place planks on an angle like that, since the question specified that planks must be "orthogonal to the sides of the pond".
          $endgroup$
          – Billy Mailman
          yesterday




          1




          1




          $begingroup$
          @Brandon_J Not just you, me too
          $endgroup$
          – Sensoray
          yesterday




          $begingroup$
          @Brandon_J Not just you, me too
          $endgroup$
          – Sensoray
          yesterday











          2












          $begingroup$

          My answer (using a computer program) is:




          There are 8777612 ways to arrange the planks.

          I solved this using a C program


          #include <stdio.h>

          #define WIDTH 10
          #define DEPTH 10
          #define PLANK 2

          unsigned long long cache[DEPTH][WIDTH];

          unsigned long long recur(int row, int col)

          int main(void)
          printf("Paths = %llun", recur(0, 0));




          Note that this is from coordinate (0,0) to (9,9) because the start and finish points are in the pond. The distance is $9$ in each direction. It checks out when manually counting small ponds.



          This also provides a generic solution for ponds up to $26 times 26$, or up to $2^64-1$ paths.

          For small ponds the cache isn't necessary.






          share|improve this answer











          $endgroup$












          • $begingroup$
            @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
            $endgroup$
            – Weather Vane
            yesterday
















          2












          $begingroup$

          My answer (using a computer program) is:




          There are 8777612 ways to arrange the planks.

          I solved this using a C program


          #include <stdio.h>

          #define WIDTH 10
          #define DEPTH 10
          #define PLANK 2

          unsigned long long cache[DEPTH][WIDTH];

          unsigned long long recur(int row, int col)

          int main(void)
          printf("Paths = %llun", recur(0, 0));




          Note that this is from coordinate (0,0) to (9,9) because the start and finish points are in the pond. The distance is $9$ in each direction. It checks out when manually counting small ponds.



          This also provides a generic solution for ponds up to $26 times 26$, or up to $2^64-1$ paths.

          For small ponds the cache isn't necessary.






          share|improve this answer











          $endgroup$












          • $begingroup$
            @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
            $endgroup$
            – Weather Vane
            yesterday














          2












          2








          2





          $begingroup$

          My answer (using a computer program) is:




          There are 8777612 ways to arrange the planks.

          I solved this using a C program


          #include <stdio.h>

          #define WIDTH 10
          #define DEPTH 10
          #define PLANK 2

          unsigned long long cache[DEPTH][WIDTH];

          unsigned long long recur(int row, int col)

          int main(void)
          printf("Paths = %llun", recur(0, 0));




          Note that this is from coordinate (0,0) to (9,9) because the start and finish points are in the pond. The distance is $9$ in each direction. It checks out when manually counting small ponds.



          This also provides a generic solution for ponds up to $26 times 26$, or up to $2^64-1$ paths.

          For small ponds the cache isn't necessary.






          share|improve this answer











          $endgroup$



          My answer (using a computer program) is:




          There are 8777612 ways to arrange the planks.

          I solved this using a C program


          #include <stdio.h>

          #define WIDTH 10
          #define DEPTH 10
          #define PLANK 2

          unsigned long long cache[DEPTH][WIDTH];

          unsigned long long recur(int row, int col)

          int main(void)
          printf("Paths = %llun", recur(0, 0));




          Note that this is from coordinate (0,0) to (9,9) because the start and finish points are in the pond. The distance is $9$ in each direction. It checks out when manually counting small ponds.



          This also provides a generic solution for ponds up to $26 times 26$, or up to $2^64-1$ paths.

          For small ponds the cache isn't necessary.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited yesterday

























          answered yesterday









          Weather VaneWeather Vane

          1,957110




          1,957110











          • $begingroup$
            @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
            $endgroup$
            – Weather Vane
            yesterday

















          • $begingroup$
            @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
            $endgroup$
            – Weather Vane
            yesterday
















          $begingroup$
          @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
          $endgroup$
          – Weather Vane
          yesterday





          $begingroup$
          @JonMarkPerry isn't the other answer for 11 x 11 pond? Count across the table.
          $endgroup$
          – Weather Vane
          yesterday


















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