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replace indentation tabs with fixed number of spaces per tab



The Next CEO of Stack OverflowThere must be a better way to replace single newlines only?Count tabs per line in text file with utilsWhat command(s) will feed a tab-delimited text file and cut each line to 80 characters?Selectively correcting LFs to CRLFsRemove fields containing specific stringReplace any number of tabs and spaces with single new line in Linux?Given a starting key token followed by n tokens, interleave the n tokens with the keyWhat does `pr -e` mean?Layout tab/spacesautomatically repair rsnapshot config: replace spaces with tabs










2















Is it possible to replace only "leading tabs" with a set number of spaces per tab? I'm defining a leading tab as one that is only preceded by tabs or spaces. I'm defining a leading or an indentation tab as one that is only preceded by whitespace.



I have the following line in my .nexrc, cribbed from this one. It runs the lines between the lines containing the mark a and the mark b through a filter. that replaces tabs.



map 2 'a!'b pr -te2


However, it replaces non-leading tabs with two spaces well, which is not ideal since a literal tab is sometimes needed.



Is there an easy and portable way to replace leading tabs only with a set number of spaces per tab?



The following perl script (which could be collapsed to a one-liner) does the job of replacing leading tabs with a width supplied on the command line, but it relies on the availability of Perl and takes quadratic time (if the file consists of nothing but tabs).



#!/usr/bin/env perl

use strict;
use warnings;

my ($width) = @ARGV;
$width //= 2;
my $replacement = ' ' x $width;

while (<>)
while (s/^(s*)t/$1$replacement/g)
print;



Here's an example of what I want to happen. ^I refers to a tab byte and # is a zero-width marker for the start of a line. The line below is a byte-ruler.



BEFORE:



#^I^I ^Ia^Ib
# 1 23 45 67


AFTER (tab width of 2)



# a^Ib
#12345678 90


AFTER (tab width of 4)



# a^Ib
#12345678901234 56









share|improve this question



















  • 2





    Are you looking for an nvi solution, or a general command-line solution?

    – Sparhawk
    2 days ago






  • 1





    expand (from GNU coreutils) would seem to be the obvious generic solution e.g. expand -it3 to replace each initial tab with 3 spaces

    – steeldriver
    2 days ago












  • sed 's/^tt*/ /' replace leading tabs with 2 spaces

    – ctac_
    2 days ago











  • sorry, I meant replacing leading tabs with two spaces per tab.

    – Gregory Nisbet
    2 days ago











  • @GregoryNisbet If you want i read it add @ before my name. You can try sed ':A;s/(^t)(t*)/2 /;tA'

    – ctac_
    2 days ago















2















Is it possible to replace only "leading tabs" with a set number of spaces per tab? I'm defining a leading tab as one that is only preceded by tabs or spaces. I'm defining a leading or an indentation tab as one that is only preceded by whitespace.



I have the following line in my .nexrc, cribbed from this one. It runs the lines between the lines containing the mark a and the mark b through a filter. that replaces tabs.



map 2 'a!'b pr -te2


However, it replaces non-leading tabs with two spaces well, which is not ideal since a literal tab is sometimes needed.



Is there an easy and portable way to replace leading tabs only with a set number of spaces per tab?



The following perl script (which could be collapsed to a one-liner) does the job of replacing leading tabs with a width supplied on the command line, but it relies on the availability of Perl and takes quadratic time (if the file consists of nothing but tabs).



#!/usr/bin/env perl

use strict;
use warnings;

my ($width) = @ARGV;
$width //= 2;
my $replacement = ' ' x $width;

while (<>)
while (s/^(s*)t/$1$replacement/g)
print;



Here's an example of what I want to happen. ^I refers to a tab byte and # is a zero-width marker for the start of a line. The line below is a byte-ruler.



BEFORE:



#^I^I ^Ia^Ib
# 1 23 45 67


AFTER (tab width of 2)



# a^Ib
#12345678 90


AFTER (tab width of 4)



# a^Ib
#12345678901234 56









share|improve this question



















  • 2





    Are you looking for an nvi solution, or a general command-line solution?

    – Sparhawk
    2 days ago






  • 1





    expand (from GNU coreutils) would seem to be the obvious generic solution e.g. expand -it3 to replace each initial tab with 3 spaces

    – steeldriver
    2 days ago












  • sed 's/^tt*/ /' replace leading tabs with 2 spaces

    – ctac_
    2 days ago











  • sorry, I meant replacing leading tabs with two spaces per tab.

    – Gregory Nisbet
    2 days ago











  • @GregoryNisbet If you want i read it add @ before my name. You can try sed ':A;s/(^t)(t*)/2 /;tA'

    – ctac_
    2 days ago













2












2








2








Is it possible to replace only "leading tabs" with a set number of spaces per tab? I'm defining a leading tab as one that is only preceded by tabs or spaces. I'm defining a leading or an indentation tab as one that is only preceded by whitespace.



I have the following line in my .nexrc, cribbed from this one. It runs the lines between the lines containing the mark a and the mark b through a filter. that replaces tabs.



map 2 'a!'b pr -te2


However, it replaces non-leading tabs with two spaces well, which is not ideal since a literal tab is sometimes needed.



Is there an easy and portable way to replace leading tabs only with a set number of spaces per tab?



The following perl script (which could be collapsed to a one-liner) does the job of replacing leading tabs with a width supplied on the command line, but it relies on the availability of Perl and takes quadratic time (if the file consists of nothing but tabs).



#!/usr/bin/env perl

use strict;
use warnings;

my ($width) = @ARGV;
$width //= 2;
my $replacement = ' ' x $width;

while (<>)
while (s/^(s*)t/$1$replacement/g)
print;



Here's an example of what I want to happen. ^I refers to a tab byte and # is a zero-width marker for the start of a line. The line below is a byte-ruler.



BEFORE:



#^I^I ^Ia^Ib
# 1 23 45 67


AFTER (tab width of 2)



# a^Ib
#12345678 90


AFTER (tab width of 4)



# a^Ib
#12345678901234 56









share|improve this question
















Is it possible to replace only "leading tabs" with a set number of spaces per tab? I'm defining a leading tab as one that is only preceded by tabs or spaces. I'm defining a leading or an indentation tab as one that is only preceded by whitespace.



I have the following line in my .nexrc, cribbed from this one. It runs the lines between the lines containing the mark a and the mark b through a filter. that replaces tabs.



map 2 'a!'b pr -te2


However, it replaces non-leading tabs with two spaces well, which is not ideal since a literal tab is sometimes needed.



Is there an easy and portable way to replace leading tabs only with a set number of spaces per tab?



The following perl script (which could be collapsed to a one-liner) does the job of replacing leading tabs with a width supplied on the command line, but it relies on the availability of Perl and takes quadratic time (if the file consists of nothing but tabs).



#!/usr/bin/env perl

use strict;
use warnings;

my ($width) = @ARGV;
$width //= 2;
my $replacement = ' ' x $width;

while (<>)
while (s/^(s*)t/$1$replacement/g)
print;



Here's an example of what I want to happen. ^I refers to a tab byte and # is a zero-width marker for the start of a line. The line below is a byte-ruler.



BEFORE:



#^I^I ^Ia^Ib
# 1 23 45 67


AFTER (tab width of 2)



# a^Ib
#12345678 90


AFTER (tab width of 4)



# a^Ib
#12345678901234 56






text-processing text-formatting






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago







Gregory Nisbet

















asked 2 days ago









Gregory NisbetGregory Nisbet

1,4981020




1,4981020







  • 2





    Are you looking for an nvi solution, or a general command-line solution?

    – Sparhawk
    2 days ago






  • 1





    expand (from GNU coreutils) would seem to be the obvious generic solution e.g. expand -it3 to replace each initial tab with 3 spaces

    – steeldriver
    2 days ago












  • sed 's/^tt*/ /' replace leading tabs with 2 spaces

    – ctac_
    2 days ago











  • sorry, I meant replacing leading tabs with two spaces per tab.

    – Gregory Nisbet
    2 days ago











  • @GregoryNisbet If you want i read it add @ before my name. You can try sed ':A;s/(^t)(t*)/2 /;tA'

    – ctac_
    2 days ago












  • 2





    Are you looking for an nvi solution, or a general command-line solution?

    – Sparhawk
    2 days ago






  • 1





    expand (from GNU coreutils) would seem to be the obvious generic solution e.g. expand -it3 to replace each initial tab with 3 spaces

    – steeldriver
    2 days ago












  • sed 's/^tt*/ /' replace leading tabs with 2 spaces

    – ctac_
    2 days ago











  • sorry, I meant replacing leading tabs with two spaces per tab.

    – Gregory Nisbet
    2 days ago











  • @GregoryNisbet If you want i read it add @ before my name. You can try sed ':A;s/(^t)(t*)/2 /;tA'

    – ctac_
    2 days ago







2




2





Are you looking for an nvi solution, or a general command-line solution?

– Sparhawk
2 days ago





Are you looking for an nvi solution, or a general command-line solution?

– Sparhawk
2 days ago




1




1





expand (from GNU coreutils) would seem to be the obvious generic solution e.g. expand -it3 to replace each initial tab with 3 spaces

– steeldriver
2 days ago






expand (from GNU coreutils) would seem to be the obvious generic solution e.g. expand -it3 to replace each initial tab with 3 spaces

– steeldriver
2 days ago














sed 's/^tt*/ /' replace leading tabs with 2 spaces

– ctac_
2 days ago





sed 's/^tt*/ /' replace leading tabs with 2 spaces

– ctac_
2 days ago













sorry, I meant replacing leading tabs with two spaces per tab.

– Gregory Nisbet
2 days ago





sorry, I meant replacing leading tabs with two spaces per tab.

– Gregory Nisbet
2 days ago













@GregoryNisbet If you want i read it add @ before my name. You can try sed ':A;s/(^t)(t*)/2 /;tA'

– ctac_
2 days ago





@GregoryNisbet If you want i read it add @ before my name. You can try sed ':A;s/(^t)(t*)/2 /;tA'

– ctac_
2 days ago










1 Answer
1






active

oldest

votes


















2














If you are looking for a generic solution using other command-line tools, one could use Awk for this.



var=$'tttnewcontent'
echo "$var" | awk ' gsub(/^[t]+/," ",$0) 1'


The command above replaces one more more occurrences of Tab with a single space i.e. 2nd argument in gsub. You can make it configurable though by generating how many spaces you want



awk -v n=5 ' BEGIN spaces = sprintf("%"n"s"," ") gsub(/^[t]+/,spaces,$0) 1'


From the last update, it seems OP wants to replace the number of leading tabs with the exact number of spaces found,



awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1'


The logic is with setting field separator to t, the number of leading tabs can be identified by doing NF-1. With the number of leading tabs identified, use it to generate the same of number of spaces from earlier sprintf() method.



You can see it by verifying the hexdump -C before and after the replacement



echo "$var" | hexdump -C
00000000 09 09 09 6e 65 77 63 6f 6e 74 65 6e 74 0a |...newcontent.|
0000000e


now with the replacement



echo "$var" | awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1' | hexdump -C
00000000 20 20 20 6e 65 77 63 6f 6e 74 65 6e 74 0a | newcontent.|
0000000e





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    active

    oldest

    votes









    2














    If you are looking for a generic solution using other command-line tools, one could use Awk for this.



    var=$'tttnewcontent'
    echo "$var" | awk ' gsub(/^[t]+/," ",$0) 1'


    The command above replaces one more more occurrences of Tab with a single space i.e. 2nd argument in gsub. You can make it configurable though by generating how many spaces you want



    awk -v n=5 ' BEGIN spaces = sprintf("%"n"s"," ") gsub(/^[t]+/,spaces,$0) 1'


    From the last update, it seems OP wants to replace the number of leading tabs with the exact number of spaces found,



    awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1'


    The logic is with setting field separator to t, the number of leading tabs can be identified by doing NF-1. With the number of leading tabs identified, use it to generate the same of number of spaces from earlier sprintf() method.



    You can see it by verifying the hexdump -C before and after the replacement



    echo "$var" | hexdump -C
    00000000 09 09 09 6e 65 77 63 6f 6e 74 65 6e 74 0a |...newcontent.|
    0000000e


    now with the replacement



    echo "$var" | awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1' | hexdump -C
    00000000 20 20 20 6e 65 77 63 6f 6e 74 65 6e 74 0a | newcontent.|
    0000000e





    share|improve this answer





























      2














      If you are looking for a generic solution using other command-line tools, one could use Awk for this.



      var=$'tttnewcontent'
      echo "$var" | awk ' gsub(/^[t]+/," ",$0) 1'


      The command above replaces one more more occurrences of Tab with a single space i.e. 2nd argument in gsub. You can make it configurable though by generating how many spaces you want



      awk -v n=5 ' BEGIN spaces = sprintf("%"n"s"," ") gsub(/^[t]+/,spaces,$0) 1'


      From the last update, it seems OP wants to replace the number of leading tabs with the exact number of spaces found,



      awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1'


      The logic is with setting field separator to t, the number of leading tabs can be identified by doing NF-1. With the number of leading tabs identified, use it to generate the same of number of spaces from earlier sprintf() method.



      You can see it by verifying the hexdump -C before and after the replacement



      echo "$var" | hexdump -C
      00000000 09 09 09 6e 65 77 63 6f 6e 74 65 6e 74 0a |...newcontent.|
      0000000e


      now with the replacement



      echo "$var" | awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1' | hexdump -C
      00000000 20 20 20 6e 65 77 63 6f 6e 74 65 6e 74 0a | newcontent.|
      0000000e





      share|improve this answer



























        2












        2








        2







        If you are looking for a generic solution using other command-line tools, one could use Awk for this.



        var=$'tttnewcontent'
        echo "$var" | awk ' gsub(/^[t]+/," ",$0) 1'


        The command above replaces one more more occurrences of Tab with a single space i.e. 2nd argument in gsub. You can make it configurable though by generating how many spaces you want



        awk -v n=5 ' BEGIN spaces = sprintf("%"n"s"," ") gsub(/^[t]+/,spaces,$0) 1'


        From the last update, it seems OP wants to replace the number of leading tabs with the exact number of spaces found,



        awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1'


        The logic is with setting field separator to t, the number of leading tabs can be identified by doing NF-1. With the number of leading tabs identified, use it to generate the same of number of spaces from earlier sprintf() method.



        You can see it by verifying the hexdump -C before and after the replacement



        echo "$var" | hexdump -C
        00000000 09 09 09 6e 65 77 63 6f 6e 74 65 6e 74 0a |...newcontent.|
        0000000e


        now with the replacement



        echo "$var" | awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1' | hexdump -C
        00000000 20 20 20 6e 65 77 63 6f 6e 74 65 6e 74 0a | newcontent.|
        0000000e





        share|improve this answer















        If you are looking for a generic solution using other command-line tools, one could use Awk for this.



        var=$'tttnewcontent'
        echo "$var" | awk ' gsub(/^[t]+/," ",$0) 1'


        The command above replaces one more more occurrences of Tab with a single space i.e. 2nd argument in gsub. You can make it configurable though by generating how many spaces you want



        awk -v n=5 ' BEGIN spaces = sprintf("%"n"s"," ") gsub(/^[t]+/,spaces,$0) 1'


        From the last update, it seems OP wants to replace the number of leading tabs with the exact number of spaces found,



        awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1'


        The logic is with setting field separator to t, the number of leading tabs can be identified by doing NF-1. With the number of leading tabs identified, use it to generate the same of number of spaces from earlier sprintf() method.



        You can see it by verifying the hexdump -C before and after the replacement



        echo "$var" | hexdump -C
        00000000 09 09 09 6e 65 77 63 6f 6e 74 65 6e 74 0a |...newcontent.|
        0000000e


        now with the replacement



        echo "$var" | awk -F$'t' ' spaces = sprintf("%"(NF-1)"s"," "); gsub(/^[t]+/,spaces,$0) 1' | hexdump -C
        00000000 20 20 20 6e 65 77 63 6f 6e 74 65 6e 74 0a | newcontent.|
        0000000e






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited yesterday

























        answered 2 days ago









        InianInian

        5,2051529




        5,2051529



























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