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Difference between -| and |- in TikZ
Insertion of perpendicular symbol at intersection of two perpendicular linesTikZ: What EXACTLY does the the |- notation for arrows do?How to Mark Right Angle in TikzHow to add perpendicular symbol at desired locationHow to fix TikZ corners in 3DTweaking behaviour of tikz trees for Feynman diagramsTikZ: how to find the intersection of two extended lines?Right Angle Symbol Alignment with TikZ/CalcWhat's the difference between path and draw in Tikz?A display indicating the definition of the distance between a point and a line (using only TikZ)How filling angle symbol?TikZ: bad line caps at the intersectionsSmoothing out angles made up of different line widthsTikZ calculate in/out-angle from nodes
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
asked yesterday
subham sonisubham soni
4,51983184
add a comment |
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
asked yesterday
subham sonisubham soni
4,51983184
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
add a comment |
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
asked yesterday
subham sonisubham soni
4,51983184
Based on this tutorial, I understand symbols -| and |- are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -| and |-.
tikz-pgf
tikz-pgf
asked yesterday
subham sonisubham soni
4,51983184
asked yesterday
subham sonisubham soni
4,51983184
asked yesterday
subham sonisubham soni
4,51983184
asked yesterday
subham sonisubham soni
4,51983184
asked yesterday
subham sonisubham soni
4,51983184
4,51983184
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
add a comment |
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
1
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
add a comment |
3 Answers
3
active
oldest
votes
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocument
Mathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocument
Mathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered yesterday
JouleVJouleV
7,89222053
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered yesterday
CarLaTeXCarLaTeX
34k551140
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
18 hours ago
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered yesterday
JouleVJouleV
7,89222053
add a comment |
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered yesterday
JouleVJouleV
7,89222053
add a comment |
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered yesterday
JouleVJouleV
7,89222053
Understand it as it looks like:
-|is "horizontal line → vertical line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) -| (y);
endtikzpicture
enddocumentMathematically,
(x,y) -| (a,b)and(x,y) -- (a,y) -- (a,b)are the same.|-is "vertical line → horizontal line":documentclass[tikz]standalone
begindocument
begintikzpicture
draw (0,0) coordinate (1) node[below] $(0,0)$;
draw (2,2) coordinate (2) node[above] $(2,2)$;
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] $(3,2)$;
draw (6,0) coordinate (y) node[below] $(5,0)$;
draw (x) |- (y);
endtikzpicture
enddocumentMathematically,
(x,y) |- (a,b)and(x,y) -- (x,b) -- (a,b)are the same.
They are clearly very different.
answered yesterday
JouleVJouleV
7,89222053
edited 14 hours ago
answered yesterday
JouleVJouleV
7,89222053
answered yesterday
JouleVJouleV
7,89222053
answered yesterday
JouleVJouleV
7,89222053
7,89222053
add a comment |
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered yesterday
CarLaTeXCarLaTeX
34k551140
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
18 hours ago
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered yesterday
CarLaTeXCarLaTeX
34k551140
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
18 hours ago
add a comment |
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered yesterday
CarLaTeXCarLaTeX
34k551140
I'd like to add to JouleV's answer another use of -| and |-.
Given two nodes, A and B:
- if you use
(A |- B)you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)you have a point with the x coordinate of B and the y coordinate of A.
documentclassarticle
usepackageamsmath
usepackagetikz
usetikzlibrarypositioning
begindocument
begintikzpicture
node[draw] (A) A;
node[draw, above right =4cm of A] (B) B;
node[draw] at (A |- B) $x$ of A, $y$ of B;
node[draw] at (A -| B) $x$ of B, $y$ of A;
endtikzpicture
enddocument
answered yesterday
CarLaTeXCarLaTeX
34k551140
edited 18 hours ago
answered yesterday
CarLaTeXCarLaTeX
34k551140
answered yesterday
CarLaTeXCarLaTeX
34k551140
answered yesterday
CarLaTeXCarLaTeX
34k551140
34k551140
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
18 hours ago
add a comment |
2
You're welcome! I edited my answer to put x and y within$...$.
– CarLaTeX
18 hours ago
2
2
You're welcome! I edited my answer to put x and y within
$...$.– CarLaTeX
18 hours ago
You're welcome! I edited my answer to put x and y within
$...$.– CarLaTeX
18 hours ago
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
PSTricks version for @CarLaTeX's explanation:
(A|-B)(TikZ) =(A|B)(PSTricks)(A-|B)(TikZ) =(B|A)(PSTricks)
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
4,99611142
add a comment |
add a comment |
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1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday