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Find path that has specific sub directory

1

Consider path in a directory structure

/A/B/C/D
/A/B/C/E
/A/B/O/P

now if I want to list all path which has sub directory C in it, then can it be done through grep?
Expected output:

/A/B/C/D
/A/B/C/E

I tried using grep and find but could not achieve this.

grep find filter

share|improve this question

edited 2 days ago

Jeff Schaller♦

44.4k1162143

asked Feb 4 '17 at 1:04

user3059993user3059993

61

add a comment | 

1

Consider path in a directory structure

/A/B/C/D
/A/B/C/E
/A/B/O/P

now if I want to list all path which has sub directory C in it, then can it be done through grep?
Expected output:

/A/B/C/D
/A/B/C/E

I tried using grep and find but could not achieve this.

grep find filter

share|improve this question

edited 2 days ago

Jeff Schaller♦

44.4k1162143

asked Feb 4 '17 at 1:04

user3059993user3059993

61

add a comment | 

Consider path in a directory structure

/A/B/C/D
/A/B/C/E
/A/B/O/P

now if I want to list all path which has sub directory C in it, then can it be done through grep?
Expected output:

/A/B/C/D
/A/B/C/E

I tried using grep and find but could not achieve this.

grep find filter

share|improve this question

edited 2 days ago

Jeff Schaller♦

44.4k1162143

asked Feb 4 '17 at 1:04

user3059993user3059993

61

/A/B/C/D
/A/B/C/E
/A/B/O/P

/A/B/C/D
/A/B/C/E

share|improve this question

edited 2 days ago

Jeff Schaller♦

44.4k1162143

asked Feb 4 '17 at 1:04

user3059993user3059993

61

share|improve this question

edited 2 days ago

Jeff Schaller♦

44.4k1162143

asked Feb 4 '17 at 1:04

user3059993user3059993

61

edited 2 days ago

Jeff Schaller♦

44.4k1162143

edited 2 days ago

Jeff Schaller♦

44.4k1162143

asked Feb 4 '17 at 1:04

user3059993user3059993

61

asked Feb 4 '17 at 1:04

user3059993user3059993

61

2 Answers
2

active

oldest

votes

3

While ka3ak's answer works, find comes with a parameter "-path" so you can simply use

find . -type d -path "*/c/*"

-path seems also a bit faster:

[hexathos:~/test] $ time find . -regextype posix-extended -regex ".*/c/.*"
./a/b/c/d
./a/b/c/e

real 0m0,013s
user 0m0,010s
sys 0m0,000s
[hexathos:~/test] $ time find . -type d -path "*/c/*"
./a/b/c/d
./a/b/c/e

real 0m0,012s
user 0m0,007s
sys 0m0,003s

share|improve this answer

answered Feb 4 '17 at 7:28

hexathoshexathos

313

add a comment | 

0

You only need find for this:

find A -type d -regextype posix-extended -regex ".*/C/.*"

For the following directory structure

A 
└── B 
 ├── C 
 │   ├── D 
 │   └── E 
 ├── C1 
 │   └── E 
 └── O
 └── P

it would return:

A/B/C/E
A/B/C/D

share|improve this answer

edited Feb 4 '17 at 9:44

answered Feb 4 '17 at 6:58

ka3akka3ak

573618

add a comment | 

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3

While ka3ak's answer works, find comes with a parameter "-path" so you can simply use

find . -type d -path "*/c/*"

-path seems also a bit faster:

[hexathos:~/test] $ time find . -regextype posix-extended -regex ".*/c/.*"
./a/b/c/d
./a/b/c/e

real 0m0,013s
user 0m0,010s
sys 0m0,000s
[hexathos:~/test] $ time find . -type d -path "*/c/*"
./a/b/c/d
./a/b/c/e

real 0m0,012s
user 0m0,007s
sys 0m0,003s

share|improve this answer

answered Feb 4 '17 at 7:28

hexathoshexathos

313

add a comment | 

3

While ka3ak's answer works, find comes with a parameter "-path" so you can simply use

find . -type d -path "*/c/*"

-path seems also a bit faster:

[hexathos:~/test] $ time find . -regextype posix-extended -regex ".*/c/.*"
./a/b/c/d
./a/b/c/e

real 0m0,013s
user 0m0,010s
sys 0m0,000s
[hexathos:~/test] $ time find . -type d -path "*/c/*"
./a/b/c/d
./a/b/c/e

real 0m0,012s
user 0m0,007s
sys 0m0,003s

share|improve this answer

answered Feb 4 '17 at 7:28

hexathoshexathos

313

add a comment | 

While ka3ak's answer works, find comes with a parameter "-path" so you can simply use

find . -type d -path "*/c/*"

-path seems also a bit faster:

[hexathos:~/test] $ time find . -regextype posix-extended -regex ".*/c/.*"
./a/b/c/d
./a/b/c/e

real 0m0,013s
user 0m0,010s
sys 0m0,000s
[hexathos:~/test] $ time find . -type d -path "*/c/*"
./a/b/c/d
./a/b/c/e

real 0m0,012s
user 0m0,007s
sys 0m0,003s

share|improve this answer

answered Feb 4 '17 at 7:28

hexathoshexathos

313

find . -type d -path "*/c/*"

[hexathos:~/test] $ time find . -regextype posix-extended -regex ".*/c/.*"
./a/b/c/d
./a/b/c/e

real 0m0,013s
user 0m0,010s
sys 0m0,000s
[hexathos:~/test] $ time find . -type d -path "*/c/*"
./a/b/c/d
./a/b/c/e

real 0m0,012s
user 0m0,007s
sys 0m0,003s

share|improve this answer

answered Feb 4 '17 at 7:28

hexathoshexathos

313

answered Feb 4 '17 at 7:28

hexathoshexathos

313

answered Feb 4 '17 at 7:28

hexathoshexathos

313

0

You only need find for this:

find A -type d -regextype posix-extended -regex ".*/C/.*"

For the following directory structure

A 
└── B 
 ├── C 
 │   ├── D 
 │   └── E 
 ├── C1 
 │   └── E 
 └── O
 └── P

it would return:

A/B/C/E
A/B/C/D

share|improve this answer

edited Feb 4 '17 at 9:44

answered Feb 4 '17 at 6:58

ka3akka3ak

573618

add a comment | 

0

You only need find for this:

find A -type d -regextype posix-extended -regex ".*/C/.*"

For the following directory structure

A 
└── B 
 ├── C 
 │   ├── D 
 │   └── E 
 ├── C1 
 │   └── E 
 └── O
 └── P

it would return:

A/B/C/E
A/B/C/D

share|improve this answer

edited Feb 4 '17 at 9:44

answered Feb 4 '17 at 6:58

ka3akka3ak

573618

add a comment | 

You only need find for this:

find A -type d -regextype posix-extended -regex ".*/C/.*"

For the following directory structure

A 
└── B 
 ├── C 
 │   ├── D 
 │   └── E 
 ├── C1 
 │   └── E 
 └── O
 └── P

it would return:

A/B/C/E
A/B/C/D

share|improve this answer

edited Feb 4 '17 at 9:44

answered Feb 4 '17 at 6:58

ka3akka3ak

573618

find A -type d -regextype posix-extended -regex ".*/C/.*"

A 
└── B 
 ├── C 
 │   ├── D 
 │   └── E 
 ├── C1 
 │   └── E 
 └── O
 └── P

A/B/C/E
A/B/C/D

share|improve this answer

edited Feb 4 '17 at 9:44

answered Feb 4 '17 at 6:58

ka3akka3ak

573618

answered Feb 4 '17 at 6:58

ka3akka3ak

573618

answered Feb 4 '17 at 6:58

ka3akka3ak

573618