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how to mask first Five digit number on keyup using *
The Next CEO of Stack OverflowHow to efficiently count the number of keys/properties of an object in JavaScript?How can I format numbers as dollars currency string in JavaScript?How do I convert a float number to a whole number in JavaScript?How do I make the first letter of a string uppercase in JavaScript?How to delay the .keyup() handler until the user stops typing?How to print a number with commas as thousands separators in JavaScriptHow to get first character of string?Calculation on keypress event (or number only in keyup event)Horizontal Multi level menu based on CSS onlyProduct, Sum, and Digits of a Number
For eg while i am typing my ssn number my first 5 dight must be masked to *
123456789 => *****6789
Note :on keyup it should check no of digits and mask based on it.
I came through this below example. It mask the entire nine digit.
https://codepen.io/anon/pen/VROrdo
javascript
New contributor
add a comment |
For eg while i am typing my ssn number my first 5 dight must be masked to *
123456789 => *****6789
Note :on keyup it should check no of digits and mask based on it.
I came through this below example. It mask the entire nine digit.
https://codepen.io/anon/pen/VROrdo
javascript
New contributor
1
Do you expect that only numbers will be in the input, or are other characters allowed too?
– CertainPerformance
2 days ago
yes only numbers will be given.no alphabetic or special character
– Robin
2 days ago
add a comment |
For eg while i am typing my ssn number my first 5 dight must be masked to *
123456789 => *****6789
Note :on keyup it should check no of digits and mask based on it.
I came through this below example. It mask the entire nine digit.
https://codepen.io/anon/pen/VROrdo
javascript
New contributor
For eg while i am typing my ssn number my first 5 dight must be masked to *
123456789 => *****6789
Note :on keyup it should check no of digits and mask based on it.
I came through this below example. It mask the entire nine digit.
https://codepen.io/anon/pen/VROrdo
javascript
javascript
New contributor
New contributor
New contributor
asked 2 days ago
RobinRobin
433
433
New contributor
New contributor
1
Do you expect that only numbers will be in the input, or are other characters allowed too?
– CertainPerformance
2 days ago
yes only numbers will be given.no alphabetic or special character
– Robin
2 days ago
add a comment |
1
Do you expect that only numbers will be in the input, or are other characters allowed too?
– CertainPerformance
2 days ago
yes only numbers will be given.no alphabetic or special character
– Robin
2 days ago
1
1
Do you expect that only numbers will be in the input, or are other characters allowed too?
– CertainPerformance
2 days ago
Do you expect that only numbers will be in the input, or are other characters allowed too?
– CertainPerformance
2 days ago
yes only numbers will be given.no alphabetic or special character
– Robin
2 days ago
yes only numbers will be given.no alphabetic or special character
– Robin
2 days ago
add a comment |
3 Answers
3
active
oldest
votes
I modified your code to mask first 5 characters. Also this is bullet proof if someone paste a copied number.
https://codepen.io/anon/pen/PLvRWw
// Replace first 5 numbers with astericks
if (displayVal.length < 6)
displayVal = displayVal.replace(/[0-9]/g, '*');
else
displayVal = '*'.repeat(5) + val.slice(5);
1
The cases look like they have a slightly different behavior ifdisplayVal
isn't purely composed of digits, since thetrue
-case replaces only digits with'*'
while thefalse
-case replaces all characters in the first 5 with'*'
.
– Nat
yesterday
add a comment |
it's worked for me https://codepen.io/anon/pen/vPwprm
<input type="text" id="fname" onkeyup="myFunction()">
function myFunction()
var x= document.getElementById("fname");
var last = x.value.substring( x.value.length - 5);
x.value.substring( x.value.length - 5);
if(x.value.length <= 5 )
x.value = x.value.substring(0, 5).replace(/d/g,"*");
add a comment |
Change your displayVal replace method regexr with following.
displayVal = displayVal.replace(/[0-9]+5/g,i=>"*****".slice(0,i.length));
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
I modified your code to mask first 5 characters. Also this is bullet proof if someone paste a copied number.
https://codepen.io/anon/pen/PLvRWw
// Replace first 5 numbers with astericks
if (displayVal.length < 6)
displayVal = displayVal.replace(/[0-9]/g, '*');
else
displayVal = '*'.repeat(5) + val.slice(5);
1
The cases look like they have a slightly different behavior ifdisplayVal
isn't purely composed of digits, since thetrue
-case replaces only digits with'*'
while thefalse
-case replaces all characters in the first 5 with'*'
.
– Nat
yesterday
add a comment |
I modified your code to mask first 5 characters. Also this is bullet proof if someone paste a copied number.
https://codepen.io/anon/pen/PLvRWw
// Replace first 5 numbers with astericks
if (displayVal.length < 6)
displayVal = displayVal.replace(/[0-9]/g, '*');
else
displayVal = '*'.repeat(5) + val.slice(5);
1
The cases look like they have a slightly different behavior ifdisplayVal
isn't purely composed of digits, since thetrue
-case replaces only digits with'*'
while thefalse
-case replaces all characters in the first 5 with'*'
.
– Nat
yesterday
add a comment |
I modified your code to mask first 5 characters. Also this is bullet proof if someone paste a copied number.
https://codepen.io/anon/pen/PLvRWw
// Replace first 5 numbers with astericks
if (displayVal.length < 6)
displayVal = displayVal.replace(/[0-9]/g, '*');
else
displayVal = '*'.repeat(5) + val.slice(5);
I modified your code to mask first 5 characters. Also this is bullet proof if someone paste a copied number.
https://codepen.io/anon/pen/PLvRWw
// Replace first 5 numbers with astericks
if (displayVal.length < 6)
displayVal = displayVal.replace(/[0-9]/g, '*');
else
displayVal = '*'.repeat(5) + val.slice(5);
answered yesterday
Masoud KeshavarzMasoud Keshavarz
77811127
77811127
1
The cases look like they have a slightly different behavior ifdisplayVal
isn't purely composed of digits, since thetrue
-case replaces only digits with'*'
while thefalse
-case replaces all characters in the first 5 with'*'
.
– Nat
yesterday
add a comment |
1
The cases look like they have a slightly different behavior ifdisplayVal
isn't purely composed of digits, since thetrue
-case replaces only digits with'*'
while thefalse
-case replaces all characters in the first 5 with'*'
.
– Nat
yesterday
1
1
The cases look like they have a slightly different behavior if
displayVal
isn't purely composed of digits, since the true
-case replaces only digits with '*'
while the false
-case replaces all characters in the first 5 with '*'
.– Nat
yesterday
The cases look like they have a slightly different behavior if
displayVal
isn't purely composed of digits, since the true
-case replaces only digits with '*'
while the false
-case replaces all characters in the first 5 with '*'
.– Nat
yesterday
add a comment |
it's worked for me https://codepen.io/anon/pen/vPwprm
<input type="text" id="fname" onkeyup="myFunction()">
function myFunction()
var x= document.getElementById("fname");
var last = x.value.substring( x.value.length - 5);
x.value.substring( x.value.length - 5);
if(x.value.length <= 5 )
x.value = x.value.substring(0, 5).replace(/d/g,"*");
add a comment |
it's worked for me https://codepen.io/anon/pen/vPwprm
<input type="text" id="fname" onkeyup="myFunction()">
function myFunction()
var x= document.getElementById("fname");
var last = x.value.substring( x.value.length - 5);
x.value.substring( x.value.length - 5);
if(x.value.length <= 5 )
x.value = x.value.substring(0, 5).replace(/d/g,"*");
add a comment |
it's worked for me https://codepen.io/anon/pen/vPwprm
<input type="text" id="fname" onkeyup="myFunction()">
function myFunction()
var x= document.getElementById("fname");
var last = x.value.substring( x.value.length - 5);
x.value.substring( x.value.length - 5);
if(x.value.length <= 5 )
x.value = x.value.substring(0, 5).replace(/d/g,"*");
it's worked for me https://codepen.io/anon/pen/vPwprm
<input type="text" id="fname" onkeyup="myFunction()">
function myFunction()
var x= document.getElementById("fname");
var last = x.value.substring( x.value.length - 5);
x.value.substring( x.value.length - 5);
if(x.value.length <= 5 )
x.value = x.value.substring(0, 5).replace(/d/g,"*");
answered 2 days ago
ahmetahmet
12811
12811
add a comment |
add a comment |
Change your displayVal replace method regexr with following.
displayVal = displayVal.replace(/[0-9]+5/g,i=>"*****".slice(0,i.length));
add a comment |
Change your displayVal replace method regexr with following.
displayVal = displayVal.replace(/[0-9]+5/g,i=>"*****".slice(0,i.length));
add a comment |
Change your displayVal replace method regexr with following.
displayVal = displayVal.replace(/[0-9]+5/g,i=>"*****".slice(0,i.length));
Change your displayVal replace method regexr with following.
displayVal = displayVal.replace(/[0-9]+5/g,i=>"*****".slice(0,i.length));
answered yesterday
Laxmikant DangeLaxmikant Dange
5,55533157
5,55533157
add a comment |
add a comment |
Robin is a new contributor. Be nice, and check out our Code of Conduct.
Robin is a new contributor. Be nice, and check out our Code of Conduct.
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1
Do you expect that only numbers will be in the input, or are other characters allowed too?
– CertainPerformance
2 days ago
yes only numbers will be given.no alphabetic or special character
– Robin
2 days ago