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Rotate a column

Type URL and show HTTP status

1

I want to make a shell script where I type an url and it returns me the status code.So far I've tested wget is there any other cause it has the tendency to save whatever you run. Then I tried to some kind awk the output but it doesn't do you have any advices.

---

Edit for Zelda:
I tried the first one

but I always receive :

P.S. Also I tried HTTP without '',now I putted for curiosity

shell-script awk wget http url

share|improve this question

edited Dec 14 '13 at 11:16

Phil_Charly

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You left out 2>&1 from the wget ... line, that makes the output to stderr go to the pipe and grep. Quotes around HTTP not needed.
  
  – Zelda
  Dec 14 '13 at 11:26
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oops, thx very much now it works
  
  – Phil_Charly
  Dec 14 '13 at 11:36
  

  
  
  
  

add a comment | 

1

I want to make a shell script where I type an url and it returns me the status code.So far I've tested wget is there any other cause it has the tendency to save whatever you run. Then I tried to some kind awk the output but it doesn't do you have any advices.

---

Edit for Zelda:
I tried the first one

but I always receive :

P.S. Also I tried HTTP without '',now I putted for curiosity

shell-script awk wget http url

share|improve this question

edited Dec 14 '13 at 11:16

Phil_Charly

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You left out 2>&1 from the wget ... line, that makes the output to stderr go to the pipe and grep. Quotes around HTTP not needed.
  
  – Zelda
  Dec 14 '13 at 11:26
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oops, thx very much now it works
  
  – Phil_Charly
  Dec 14 '13 at 11:36
  

  
  
  
  

add a comment | 

I want to make a shell script where I type an url and it returns me the status code.So far I've tested wget is there any other cause it has the tendency to save whatever you run. Then I tried to some kind awk the output but it doesn't do you have any advices.

---

Edit for Zelda:
I tried the first one

but I always receive :

P.S. Also I tried HTTP without '',now I putted for curiosity

shell-script awk wget http url

share|improve this question

edited Dec 14 '13 at 11:16

Phil_Charly

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

share|improve this question

edited Dec 14 '13 at 11:16

Phil_Charly

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

share|improve this question

edited Dec 14 '13 at 11:16

Phil_Charly

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

asked Dec 14 '13 at 9:59

Phil_CharlyPhil_Charly

863514

2 Answers
2

active

oldest

votes

9

You can simply use curl for it. I have written a simple script for it.

url=$1
curl -sL $url -w "%http_code %url_effective\n" "URL" -o /dev/null

Where URL is your URL which you have to test output will gives you status.

Example

share|improve this answer

edited May 27 '15 at 21:03

David Kennedy

95081738

answered Dec 14 '13 at 10:37

user37323

add a comment | 

4

You can just stick with wget:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP

that gives you:

HTTP request sent, awaiting response... 200 OK

which you can further trim with cut:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP | cut -d ' ' -f 6

If the url does not exist, then there is no output.

With query for url:

echo "give your url"
read url
wget -O /dev/null $url 2>&1 | grep -F HTTP
echo "ok?"

share|improve this answer

edited Dec 14 '13 at 11:29

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526

add a comment | 

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9

You can simply use curl for it. I have written a simple script for it.

url=$1
curl -sL $url -w "%http_code %url_effective\n" "URL" -o /dev/null

Where URL is your URL which you have to test output will gives you status.

Example

share|improve this answer

edited May 27 '15 at 21:03

David Kennedy

95081738

answered Dec 14 '13 at 10:37

user37323

add a comment | 

9

You can simply use curl for it. I have written a simple script for it.

url=$1
curl -sL $url -w "%http_code %url_effective\n" "URL" -o /dev/null

Where URL is your URL which you have to test output will gives you status.

Example

share|improve this answer

edited May 27 '15 at 21:03

David Kennedy

95081738

answered Dec 14 '13 at 10:37

user37323

add a comment | 

You can simply use curl for it. I have written a simple script for it.

url=$1
curl -sL $url -w "%http_code %url_effective\n" "URL" -o /dev/null

Where URL is your URL which you have to test output will gives you status.

Example

share|improve this answer

edited May 27 '15 at 21:03

David Kennedy

95081738

answered Dec 14 '13 at 10:37

user37323

url=$1
curl -sL $url -w "%http_code %url_effective\n" "URL" -o /dev/null

share|improve this answer

edited May 27 '15 at 21:03

David Kennedy

95081738

answered Dec 14 '13 at 10:37

user37323

edited May 27 '15 at 21:03

David Kennedy

95081738

edited May 27 '15 at 21:03

David Kennedy

95081738

4

You can just stick with wget:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP

that gives you:

HTTP request sent, awaiting response... 200 OK

which you can further trim with cut:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP | cut -d ' ' -f 6

If the url does not exist, then there is no output.

With query for url:

echo "give your url"
read url
wget -O /dev/null $url 2>&1 | grep -F HTTP
echo "ok?"

share|improve this answer

edited Dec 14 '13 at 11:29

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526

add a comment | 

4

You can just stick with wget:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP

that gives you:

HTTP request sent, awaiting response... 200 OK

which you can further trim with cut:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP | cut -d ' ' -f 6

If the url does not exist, then there is no output.

With query for url:

echo "give your url"
read url
wget -O /dev/null $url 2>&1 | grep -F HTTP
echo "ok?"

share|improve this answer

edited Dec 14 '13 at 11:29

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526

add a comment | 

You can just stick with wget:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP

that gives you:

HTTP request sent, awaiting response... 200 OK

which you can further trim with cut:

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP | cut -d ' ' -f 6

If the url does not exist, then there is no output.

With query for url:

echo "give your url"
read url
wget -O /dev/null $url 2>&1 | grep -F HTTP
echo "ok?"

share|improve this answer

edited Dec 14 '13 at 11:29

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP

HTTP request sent, awaiting response... 200 OK

wget -O /dev/null http://unix.stackexchange.com 2>&1 | grep -F HTTP | cut -d ' ' -f 6

echo "give your url"
read url
wget -O /dev/null $url 2>&1 | grep -F HTTP
echo "ok?"

share|improve this answer

edited Dec 14 '13 at 11:29

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526

answered Dec 14 '13 at 10:54

ZeldaZelda

4,8521526