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Adding up numbers in Portuguese is strange
How does one go about picking words when creating Verbal Arithmetic puzzles?SPEND LESS MONEY alphameticHow do I solve cryptarithmetic puzzles?Letters = numbersNumbers = letters 2.0Does AAA+BBB+CCC+DDD=ABCD have a solution for distinct digits A,B,C,D?Arrange numbers to 3 different math operationsSum of three six digit numbersWhat are these numbers?
$begingroup$
My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:
D O I S
D O I S
+ ________
O I T O
Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?
Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.
alphametic
asked yesterday
ChaoticChaotic
621316
$endgroup$
add a comment |
$begingroup$
My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:
D O I S
D O I S
+ ________
O I T O
Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?
Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.
alphametic
asked yesterday
ChaoticChaotic
621316
$endgroup$
add a comment |
$begingroup$
My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:
D O I S
D O I S
+ ________
O I T O
Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?
Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.
alphametic
asked yesterday
ChaoticChaotic
621316
$endgroup$
My friend from Portugal said that 2 + 2 is 8 in Portuguese. And he could prove it. I did not understand it at first. But then he showed me the following equation:
D O I S
D O I S
+ ________
O I T O
Ah, now it is clear. Two is "dois" and eight is "oito" in Portuguese. And the equation above makes perfect sense. Could you solve the single one solution that explain this?
Rules: D, O, I, S and T are a number between 0 - 9. Each one is unique.
alphametic
alphametic
asked yesterday
ChaoticChaotic
621316
asked yesterday
ChaoticChaotic
621316
asked yesterday
ChaoticChaotic
621316
asked yesterday
ChaoticChaotic
621316
asked yesterday
ChaoticChaotic
621316
621316
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Could it be
1246
+ 1246
------
2492
Then
D=1, O=2, I=4, S=6, T=9
edited 15 hours ago
Omega Krypton
4,8302444
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
$endgroup$
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
1
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
add a comment |
$begingroup$
From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
$endgroup$
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
add a comment |
$begingroup$
Let's start as a basic Brute Force
Consider D as 1
Since D and S gives a Unit Place as O
So,S is D+5 ;S is 6
So, Here O is 2
Given I = O + O; So,I=4
Since T is I+I with a carry of 1 ;T is 9
edited 20 hours ago
JonMark Perry
20.4k64099
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Could it be
1246
+ 1246
------
2492
Then
D=1, O=2, I=4, S=6, T=9
edited 15 hours ago
Omega Krypton
4,8302444
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
$endgroup$
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
1
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
add a comment |
$begingroup$
Could it be
1246
+ 1246
------
2492
Then
D=1, O=2, I=4, S=6, T=9
edited 15 hours ago
Omega Krypton
4,8302444
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
$endgroup$
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
1
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
add a comment |
$begingroup$
Could it be
1246
+ 1246
------
2492
Then
D=1, O=2, I=4, S=6, T=9
edited 15 hours ago
Omega Krypton
4,8302444
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
$endgroup$
Could it be
1246
+ 1246
------
2492
Then
D=1, O=2, I=4, S=6, T=9
edited 15 hours ago
Omega Krypton
4,8302444
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
edited 15 hours ago
Omega Krypton
4,8302444
edited 15 hours ago
Omega Krypton
4,8302444
edited 15 hours ago
Omega Krypton
4,8302444
4,8302444
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
answered 23 hours ago
El-GuestEl-Guest
20.8k24791
20.8k24791
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
1
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
add a comment |
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
1
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
$begingroup$
Perfect! Easy one?
$endgroup$
– Chaotic
23 hours ago
1
1
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
$begingroup$
Not super easy, but there were a limited number of combinations to try. Good puzzle @Chaotic!
$endgroup$
– El-Guest
16 hours ago
add a comment |
$begingroup$
From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
$endgroup$
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
add a comment |
$begingroup$
From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
$endgroup$
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
add a comment |
$begingroup$
From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
$endgroup$
From $S+S=O$ we know $O$ is even. From the $O+O$ part, we know $Ole4$ because $2O$ doesn't carry (otherwise $O$ would also have to be odd). Therefore $I$ is doubly even ($I=2O$), and because $2I$ doesn't carry, $I=4$ and $O=2$. $D=Spm5$ and $2D$ doesn't carry, so $S=6$ and $D=1$. $T=2I+1=9$.
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
edited 19 hours ago
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
answered 23 hours ago
JonMark PerryJonMark Perry
20.4k64099
20.4k64099
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
add a comment |
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
$begingroup$
You haven't given a value for $T$.
$endgroup$
– ZanyG
22 hours ago
add a comment |
$begingroup$
Let's start as a basic Brute Force
Consider D as 1
Since D and S gives a Unit Place as O
So,S is D+5 ;S is 6
So, Here O is 2
Given I = O + O; So,I=4
Since T is I+I with a carry of 1 ;T is 9
edited 20 hours ago
JonMark Perry
20.4k64099
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Let's start as a basic Brute Force
Consider D as 1
Since D and S gives a Unit Place as O
So,S is D+5 ;S is 6
So, Here O is 2
Given I = O + O; So,I=4
Since T is I+I with a carry of 1 ;T is 9
edited 20 hours ago
JonMark Perry
20.4k64099
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Let's start as a basic Brute Force
Consider D as 1
Since D and S gives a Unit Place as O
So,S is D+5 ;S is 6
So, Here O is 2
Given I = O + O; So,I=4
Since T is I+I with a carry of 1 ;T is 9
edited 20 hours ago
JonMark Perry
20.4k64099
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Let's start as a basic Brute Force
Consider D as 1
Since D and S gives a Unit Place as O
So,S is D+5 ;S is 6
So, Here O is 2
Given I = O + O; So,I=4
Since T is I+I with a carry of 1 ;T is 9
edited 20 hours ago
JonMark Perry
20.4k64099
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 20 hours ago
JonMark Perry
20.4k64099
edited 20 hours ago
JonMark Perry
20.4k64099
edited 20 hours ago
JonMark Perry
20.4k64099
20.4k64099
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
answered 22 hours ago
NaveenGopal NolluNaveenGopal Nollu
1
1
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
NaveenGopal Nollu is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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