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Bash script fails where command line works

0

I wrote a basic bash function to test for the occurence of a string search argument in another string. Running it from the command line gives expected results. Running the same from a shell script fails. Can somebody show me the errors of my ways?

me@mylaptop $ line='someidentifier 123 another identifier 789 065 theend'
me@mylaptop $ sarg='+([0-9])+([ ])another identifier'
me@mylaptop $ type strstr
strstr is a function
strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0

me@mylaptop $ strstr "$line" "$sarg" ; echo "$?"
0
me@mylaptop $

My script:

me@mylaptop $ cat l.sh
#!/bin/bash

function strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0


line='someidentifier 123 another identifier 789 065 theend'
sarg='+([0-9])+([ ])another identifier'

echo '==='"$line"'==='

echo '==='"$sarg"'==='

strstr "$line" "$sarg"

echo "$?"

me@mylaptop $ ./l.sh
===someidentifier 123 another identifier 789 065 theend===
===+([0-9])+([ ])another identifier===
1
me@mylaptop $

bash bash-expansion

share|improve this question

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

asked 20 hours ago

JdeHaanJdeHaan

359214

add a comment | 

0

I wrote a basic bash function to test for the occurence of a string search argument in another string. Running it from the command line gives expected results. Running the same from a shell script fails. Can somebody show me the errors of my ways?

me@mylaptop $ line='someidentifier 123 another identifier 789 065 theend'
me@mylaptop $ sarg='+([0-9])+([ ])another identifier'
me@mylaptop $ type strstr
strstr is a function
strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0

me@mylaptop $ strstr "$line" "$sarg" ; echo "$?"
0
me@mylaptop $

My script:

me@mylaptop $ cat l.sh
#!/bin/bash

function strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0


line='someidentifier 123 another identifier 789 065 theend'
sarg='+([0-9])+([ ])another identifier'

echo '==='"$line"'==='

echo '==='"$sarg"'==='

strstr "$line" "$sarg"

echo "$?"

me@mylaptop $ ./l.sh
===someidentifier 123 another identifier 789 065 theend===
===+([0-9])+([ ])another identifier===
1
me@mylaptop $

bash bash-expansion

share|improve this question

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

asked 20 hours ago

JdeHaanJdeHaan

359214

add a comment | 

I wrote a basic bash function to test for the occurence of a string search argument in another string. Running it from the command line gives expected results. Running the same from a shell script fails. Can somebody show me the errors of my ways?

me@mylaptop $ line='someidentifier 123 another identifier 789 065 theend'
me@mylaptop $ sarg='+([0-9])+([ ])another identifier'
me@mylaptop $ type strstr
strstr is a function
strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0

me@mylaptop $ strstr "$line" "$sarg" ; echo "$?"
0
me@mylaptop $

My script:

me@mylaptop $ cat l.sh
#!/bin/bash

function strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0


line='someidentifier 123 another identifier 789 065 theend'
sarg='+([0-9])+([ ])another identifier'

echo '==='"$line"'==='

echo '==='"$sarg"'==='

strstr "$line" "$sarg"

echo "$?"

me@mylaptop $ ./l.sh
===someidentifier 123 another identifier 789 065 theend===
===+([0-9])+([ ])another identifier===
1
me@mylaptop $

bash bash-expansion

share|improve this question

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

asked 20 hours ago

JdeHaanJdeHaan

359214

me@mylaptop $ line='someidentifier 123 another identifier 789 065 theend'
me@mylaptop $ sarg='+([0-9])+([ ])another identifier'
me@mylaptop $ type strstr
strstr is a function
strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0

me@mylaptop $ strstr "$line" "$sarg" ; echo "$?"
0
me@mylaptop $

me@mylaptop $ cat l.sh
#!/bin/bash

function strstr ()

 [ "$1#*$2*" = "$1" ] && return 1;
 return 0


line='someidentifier 123 another identifier 789 065 theend'
sarg='+([0-9])+([ ])another identifier'

echo '==='"$line"'==='

echo '==='"$sarg"'==='

strstr "$line" "$sarg"

echo "$?"

me@mylaptop $ ./l.sh
===someidentifier 123 another identifier 789 065 theend===
===+([0-9])+([ ])another identifier===
1
me@mylaptop $

share|improve this question

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

asked 20 hours ago

JdeHaanJdeHaan

359214

share|improve this question

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

asked 20 hours ago

JdeHaanJdeHaan

359214

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

edited 20 hours ago

Rui F Ribeiro

41.6k1483141

asked 20 hours ago

JdeHaanJdeHaan

359214

asked 20 hours ago

JdeHaanJdeHaan

359214

1 Answer
1

active

oldest

votes

4

You have enabled the extglob shell option in your interactive shell, but not in your script:

$ strstr "$line" "$sarg" ; echo "$?"
1
$ shopt -s extglob
$ strstr "$line" "$sarg" ; echo "$?"
0

Note that your function could be simplified into

strstr () 
 [ "$1#*$2*" != "$1" ]

share|improve this answer

answered 19 hours ago

KusalanandaKusalananda

136k17257426

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Correct. Perfect. Thanks. Both for the solution and the improvement.
  
  – JdeHaan
  19 hours ago
  

  
  
  
  

add a comment | 

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4

You have enabled the extglob shell option in your interactive shell, but not in your script:

$ strstr "$line" "$sarg" ; echo "$?"
1
$ shopt -s extglob
$ strstr "$line" "$sarg" ; echo "$?"
0

Note that your function could be simplified into

strstr () 
 [ "$1#*$2*" != "$1" ]

share|improve this answer

answered 19 hours ago

KusalanandaKusalananda

136k17257426

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Correct. Perfect. Thanks. Both for the solution and the improvement.
  
  – JdeHaan
  19 hours ago
  

  
  
  
  

add a comment | 

4

You have enabled the extglob shell option in your interactive shell, but not in your script:

$ strstr "$line" "$sarg" ; echo "$?"
1
$ shopt -s extglob
$ strstr "$line" "$sarg" ; echo "$?"
0

Note that your function could be simplified into

strstr () 
 [ "$1#*$2*" != "$1" ]

share|improve this answer

answered 19 hours ago

KusalanandaKusalananda

136k17257426

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Correct. Perfect. Thanks. Both for the solution and the improvement.
  
  – JdeHaan
  19 hours ago
  

  
  
  
  

add a comment | 

You have enabled the extglob shell option in your interactive shell, but not in your script:

$ strstr "$line" "$sarg" ; echo "$?"
1
$ shopt -s extglob
$ strstr "$line" "$sarg" ; echo "$?"
0

Note that your function could be simplified into

strstr () 
 [ "$1#*$2*" != "$1" ]

share|improve this answer

answered 19 hours ago

KusalanandaKusalananda

136k17257426

$ strstr "$line" "$sarg" ; echo "$?"
1
$ shopt -s extglob
$ strstr "$line" "$sarg" ; echo "$?"
0

strstr () 
 [ "$1#*$2*" != "$1" ]

share|improve this answer

answered 19 hours ago

KusalanandaKusalananda

136k17257426

answered 19 hours ago

KusalanandaKusalananda

136k17257426

answered 19 hours ago

KusalanandaKusalananda

136k17257426