Ygtjki

I'm trying to draw a derivation tree for a simple grammar using tikz-qtree.

Here is my current code:

documentclass[11pt]article
usepackagetikz
usetikzlibraryshapes,arrows,calc
usepackagetikz-qtree

% ----------

begindocument
 begintikzpicture
 tikzsetgrow'=right
 tikzsetevery tree node/.style=anchor=base west
 Tree [.$SS$ [.$(S)$ $()$]
 [.$(S)$
 [.$((S))$ $(())$]
 ]
 ]
 endtikzpicture
enddocument

My intended result looks like this:

 -(S)------------() 
 -/ 
 -/ 
 -/ 
 -/ 
 -/ 
 SS - 
 - 
 - 
 - 
 - 
 - 
 -(S)---------((S))----------(())

When I compile the document, I get a bunch of missing end brace complaints "./main.tex:21: Missing } inserted", but the square brackets in the Tree are balanced as far as I can see.

What am I doing wrong?

Here are three different ways to draw the graph

tikz-qtree solution

Take care of the white space!

documentclass[11pt]article
usepackagetikz
usetikzlibraryshapes,arrows,calc
usepackagetikz-qtree

% ----------

begindocument
begintikzpicture
tikzsetgrow'=right
tikzsetevery tree node/.style=anchor=base west
Tree [.$SS$ [.$(S)$ $()$ ] [.$(S)$ [.$((S))$ $(())$ ] ] ]
endtikzpicture
enddocument

Pure TikZ solution

documentclass[tikz]standalone
usetikzlibrarypositioning
begindocument
begintikzpicture[node distance=0.5cm]
node (ss) $SS$;
node[above right=of ss] (sa) $(S)$;
node[right=of sa] (br1) $()$;
node[below right=of ss] (sb) $(S)$;
node[right=of sb] (ssb) $((S))$;
node[right=of ssb] (br2) $(())$;
draw (br1) -- (sa) -- (ss) -- (sb) -- (ssb) -- (br2);
endtikzpicture
enddocument

tikzcd solution

documentclassstandalone
usepackagetikz-cd
begindocument
begintikzcd[every arrow/.append style=dash]
& (S) arrow[r] & ()\
SS arrow[ru]arrow[rd] & &\
& (S) arrow[r] & ((S)) arrow[r] & (())
endtikzcd
enddocument

I'd like to persuade you to switch to forest.

documentclassarticle
usepackage[edges]forest
begindocument
beginforest
for tree=grow=east
 [$SS$ 
 [$(S)$ $()$]
 [$(S)$
 [$((S))$ $(())$]
 ]
 ]
endforest
enddocument