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Which one is the true statement? [on hold]
The Next CEO of Stack OverflowIs the dog dead or alive?The dark side of the moonWho is the horse thief?Make the statement true!Statements that the deities True and False cannot sayA false and a true statement in the blue-eyed puzzleDetermine which statements are True, and which statements are False5x5 statement tableKnights, Knaves and Normals - the tough oneTrue or Faulse?
$begingroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
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put on hold as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel 17 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
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|
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$begingroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
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put on hold as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel 17 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
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Ha! Great puzzle! $(+1),colororangebigstar$
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– user477343
yesterday
2
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Is this an original puzzle?
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– Dr Xorile
yesterday
2
$begingroup$
brainly.in/question/8878122
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– Paul Evans
yesterday
4
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@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
23 hours ago
1
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
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– Paul Evans
11 hours ago
|
show 3 more comments
$begingroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
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$endgroup$
- All five statements below are true.
- None of the four statements below are true.
- Both of the statements above are true.
- Exactly one of the three statements above is true.
- None of the four statements above are true.
- None of the five statements above are true.
logical-deduction
logical-deduction
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edited 2 days ago
Deusovi♦
62.5k6215269
62.5k6215269
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asked 2 days ago
giorgi rcheulishviligiorgi rcheulishvili
1236
1236
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put on hold as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel 17 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel
put on hold as off-topic by Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel 17 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – Brandon_J, Alconja, Omega Krypton, Peregrine Rook, Glorfindel
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
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– user477343
yesterday
2
$begingroup$
Is this an original puzzle?
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– Dr Xorile
yesterday
2
$begingroup$
brainly.in/question/8878122
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– Paul Evans
yesterday
4
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@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
23 hours ago
1
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
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– Paul Evans
11 hours ago
|
show 3 more comments
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Ha! Great puzzle! $(+1),colororangebigstar$
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– user477343
yesterday
2
$begingroup$
Is this an original puzzle?
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– Dr Xorile
yesterday
2
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
yesterday
4
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@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
23 hours ago
1
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
11 hours ago
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– user477343
yesterday
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– user477343
yesterday
2
2
$begingroup$
Is this an original puzzle?
$endgroup$
– Dr Xorile
yesterday
$begingroup$
Is this an original puzzle?
$endgroup$
– Dr Xorile
yesterday
2
2
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
yesterday
$begingroup$
brainly.in/question/8878122
$endgroup$
– Paul Evans
yesterday
4
4
$begingroup$
@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
23 hours ago
$begingroup$
@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
23 hours ago
1
1
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
11 hours ago
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
$endgroup$
– Paul Evans
11 hours ago
|
show 3 more comments
8 Answers
8
active
oldest
votes
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This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
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add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
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Thanks!!!!!!!!!
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– Tojrah
2 days ago
1
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(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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– Rubio♦
2 days ago
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Thanks!!!!!!!!!
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– Tojrah
yesterday
add a comment |
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Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
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Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
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– aschepler
yesterday
add a comment |
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The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
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add a comment |
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
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add a comment |
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
add a comment |
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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add a comment |
8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
$endgroup$
add a comment |
$begingroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
$endgroup$
add a comment |
$begingroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
$endgroup$
This is the line of thought I followed:
Statement #3
is impossible because of #1 and #2 contradicting each other (let's consider only the last three statements, for simplicity). So, #3 must be false.
As a consequence,
#1 must be false.
If #4 were true, then #2 must be true (by exclusion), but this would imply that #4 itself is false. Then,
#4 is false.
If #5 were true,
then #2 must be false. So far, this holds.
If #5 were false, then #2, by exclusion, must be true. But this implies that #3 is true too, which is a contradiction, as seen above.
Then #5 is true, and #2 is false.
Accordingly,
#6 is false because it being true would imply that #5 is false.
In conclusion,
there is only one true statement, as said in the title, and is #5.
edited 2 days ago
answered 2 days ago
dr01dr01
646926
646926
add a comment |
add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
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Thanks!!!!!!!!!
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– Tojrah
2 days ago
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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– Rubio♦
2 days ago
$begingroup$
Thanks!!!!!!!!!
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– Tojrah
yesterday
add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
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Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$begingroup$
Thanks!!!!!!!!!
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– Tojrah
2 days ago
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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– Rubio♦
2 days ago
$begingroup$
Thanks!!!!!!!!!
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– Tojrah
yesterday
add a comment |
$begingroup$
True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
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Tojrah is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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True statement is
5th statement
Reason
1 is false(only 5 is true)
2 is false(5 is true)
3 is false(both above are false)
4 is false(all are false)
6 is false(5is true)
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edited yesterday
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answered 2 days ago
TojrahTojrah
2313
2313
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Thanks!!!!!!!!!
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– Tojrah
2 days ago
1
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(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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– Rubio♦
2 days ago
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Thanks!!!!!!!!!
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– Tojrah
yesterday
add a comment |
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Thanks!!!!!!!!!
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– Tojrah
2 days ago
1
$begingroup$
(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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– Rubio♦
2 days ago
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Thanks!!!!!!!!!
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– Tojrah
yesterday
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Thanks!!!!!!!!!
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– Tojrah
2 days ago
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Thanks!!!!!!!!!
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– Tojrah
2 days ago
1
1
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(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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2 days ago
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(A space after >! is not required. However, you cannot follow a spoiler line immediately with a non-spoiler line; it will break the formatting. A blank line after the spoilered line(s) suffices.)
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2 days ago
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Thanks!!!!!!!!!
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– Tojrah
yesterday
$begingroup$
Thanks!!!!!!!!!
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– Tojrah
yesterday
add a comment |
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Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
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Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
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– aschepler
yesterday
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Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
$endgroup$
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
yesterday
add a comment |
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Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
$endgroup$
Another nice way to approach this puzzle is by constructing chains of implications. We know there's only one true statement, so if one statement implies another one, then it's false.
Firstly, $3Rightarrow1Rightarrow6Rightarrow5$, so $3$ and $1$ and $6$ are false.
Since $3$ and $1$ are not true, $4Leftrightarrow2$, so they're both false.
The only option left is $5$, so this is the answer.
answered 2 days ago
Rand al'ThorRand al'Thor
71k14235471
71k14235471
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
yesterday
add a comment |
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
yesterday
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
yesterday
$begingroup$
Except it's also possible to uniquely determine each statement's truth value without assuming the title question implies any fact.
$endgroup$
– aschepler
yesterday
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
$endgroup$
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
$endgroup$
add a comment |
$begingroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
$endgroup$
The correct one is
5
Explanation:
1 is not possible, as only one is true.
2 is not possible, as it makes 4 true.
3 is not possible for similar reasons.
4 is not true as it makes one of 1, 2 or 3 true as well.
6 is self-contradictory.
answered 2 days ago
Krad CigolKrad Cigol
1,046210
1,046210
add a comment |
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Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
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add a comment |
$begingroup$
Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
$endgroup$
add a comment |
$begingroup$
Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
$endgroup$
Same answer as everyone else, slightly different reasoning
1 must be false (if true then 6 would be true and contradict it).
=> 3 is false.
As a result, if 2 were true then 4 would also be true, contradicting "which one statement", so 2 is false.
=> 4 is false
Trivially 5 is true, 6 is false.
answered yesterday
StilezStilez
1,224211
1,224211
add a comment |
add a comment |
$begingroup$
My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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My Answer
Statement 5 is the true statement.
Explanation
If Statement 1 is true then Statement 6 is true; however, statements 1 and 6 cannot both be true as they are mutually contradictory; therefore, Statement 1 is false.
If Statement 1 is false then Statement 3 is also false.
If 2 is true then 4 would be false; However, if statement 4 is false then statement 2 is negated. It is logically impossible for statement 2 to be true.
If 1, 2, and 3 are false then 4 is also false.
If 1, 2, 3, and 4 are false then 5 is true.
Finally, if 5 is true then 6 is false.
Hence, statement 5 is the only true statement.
edit: you can also eliminate statements 1 and 3 immediately because they imply that more than one statement is true while the questions states that there is only one true statement.
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edited yesterday
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answered yesterday
KRAKRA
113
113
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
add a comment |
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
add a comment |
$begingroup$
I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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I have used substitution to determine the only true statement.
Indeed, I started by writing the logic equivalents of each statement.
$$1 leftarrow 2 land 3 land 4 land 5 land 6$$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot 6$$
$$3 leftarrow 1 land 2$$
$$4 leftarrow (1 land lnot 2 land lnot 3) lor ( lnot 1 land 2 land lnot 3) lor ( lnot 1 land lnot 2 land 3)$$
$$5 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4$$
$$6 leftarrow lnot 1 land lnot 2 land lnot 3 land lnot 4 land lnot 5$$
From this, a simple replacement in $6$ gives us
$$6 leftarrow 5 land lnot 5$$
Which really is just,
$$6 leftarrow F$$
From there, you simply substitute the result in the other equations
$$1 leftarrow 2 land 3 land 4 land 5 land F $$
$$2 leftarrow lnot 3 land lnot 4 land lnot 5 land lnot F $$
Which gives us
$$ 1 leftarrow F $$
Again, substitution...
$$3 leftarrow F land 2$$
$$4 leftarrow (F land lnot 2 land lnot 3) lor ( lnot F land 2 land lnot 3) lor ( lnot F land lnot 2 land 3)$$
$$5 leftarrow lnot F land lnot 2 land lnot 3 land lnot 4 $$
Simplifying to
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow (F) lor (2 land T) lor (F) $$
$$5 leftarrow T land lnot 2 land T land lnot 4 $$
$$6 leftarrow F $$
At this point, we can simply rewrite as:
$$1 leftarrow F $$
$$2 leftarrow lnot 4 land lnot 5 $$
$$3 leftarrow F $$
$$4 leftarrow 2 $$
$$5 leftarrow lnot 2 $$
$$6 leftarrow F $$
This gives us the satisfaction that, in fact,
$$ 2 leftarrow lnot 2 land lnot lnot 2 $$
Which is a contradiction, thence
$$ 2 leftarrow F $$
Giving us the solution
$$5 leftarrow T $$
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answered yesterday
Theophile DanoTheophile Dano
1112
1112
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
add a comment |
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
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Welcome to Puzzling SE!
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– SteveV
23 hours ago
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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add a comment |
$begingroup$
Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
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add a comment |
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Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
$endgroup$
Alright, here's my try. I think I have a fairly straightforward explanation.
1. All five statements below are true.
2. None of the four statements below are true.
3. Both of the statements above are true.
4. Exactly one of the three statements above is true.
5. None of the four statements above are true.
6. None of the five statements above are true.
We can instantly eliminate
Statements 1, 3, and 4.
Why?
Well, they all say that there is another true answer. The design of the question precludes this from being true - "Which one is the true statement?" (emphasis mine).
This leaves
Statements 2, 5, and 6. We need a way to make two of them false. Statement 6 cannot be the true statement - it would make statement 5 true, which would make statement 6 false. Statement 2 and 5 can be true, if the other is false. Ignoring previously eliminated statements, statement 2 says statement 5 is false. Statement 5 says statement 2 is false. However, if statement 2 were true, statement 3 is also true.
Thus, as a final answer,
Statement 5 would work.
answered 20 hours ago
Brandon_JBrandon_J
3,175240
3,175240
add a comment |
add a comment |
$begingroup$
Ha! Great puzzle! $(+1),colororangebigstar$
$endgroup$
– user477343
yesterday
2
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Is this an original puzzle?
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– Dr Xorile
yesterday
2
$begingroup$
brainly.in/question/8878122
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– Paul Evans
yesterday
4
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@PaulEvans' link suggests that the puzzle has been posted elsewhere before. We require sources to be listed to avoid plagerism. Even if you are the author of the other link, then just let us know that. Or you could cite the other link and state that you came up with it independently. It's a policy of this forum
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– Dr Xorile
23 hours ago
1
$begingroup$
@giorgircheulishvili Have a look, it's not modified. It's word-for-word identical.
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– Paul Evans
11 hours ago