Ygtjki

Here is my program,

item_no = []
max = 0
for i in range(5):
 input_no = int(input("Enter an item number: "))
 item_no.append(input_no)
for i in item_no:
 if i > max:
 max = i
high = item_no.index(max)
print (item_no[high])

Example input: [5, 6, 7, 8, 8]

Example output: 8

How can I change my program to output the same highest numbers in an array?

Expected output: [8, 8]

Just get the maximum using max and then its count and combine the two in a list-comprehension.

item_no = [5, 6, 7, 8, 8]

max_no = max(item_no)
highest = [max_no for _ in range(item_no.count(max_no))]
print(highest) # -> [8, 8]

Note that this will return a list of a single item in case your maximum value appears only once.

A solution closer to your current programming style would be the following:

item_no = [5, 6, 7, 8, 8]
max_no = 0
for i in item_no:
 if i > max_no:
 max_no = i
 high = [i]
 elif i == max_no:
 high.append(i)

with the same results as above of course.

Note that this last one is less efficient than the first by quite a margin. Python allows you to be more efficient than these explicit, fortran-like loops and it is more efficient itself when you use it properly.

You can do it even shorter:

item_no = [5, 6, 7, 8, 8]
#compute once - use many
max_item = max(item_no)
print(item_no.count(max_item) * [max_item])

output:

[8, 8]

You could use list comprehension for that task following way:

numbers = [5, 6, 7, 8, 8]
maxnumbers = [i for i in numbers if i==max(numbers)]
print(*maxnumbers,sep=',')

output:

8,8

* operator in print is used to unpack values, sep is used to inform print what seperator to use: , in this case.

EDIT: If you want to get indices of biggest value and call max only once then do:

numbers = [5, 6, 7, 8, 8]
biggest = max(numbers)
positions = [inx for inx,i in enumerate(numbers) if i==biggest]
print(*positions,sep=',')

Output:

3,4

As you might check numbers[3] is equal to biggest and numbers[4] is equal to biggest.

1. Count the occurrence of max number




2. iterate over the list to print the max number for the range of the count (1)

Hence:

item_no = [5, 6, 7, 8, 8]
counter = item_no.count(max(item_no)) # 2
print([max(item_no) for x in range(counter)]) 

OUTPUT:

[8, 8]